Questions: Solve the following KenKen puzzle. 1 2 3 4 --------------- A 4 2 B 3 1 C 2 1- 1- D 7+ 1

Solve the following KenKen puzzle.

    1  2  3  4 
---------------
 A     4     2 
 B  3     1    
 C  2  1-     1- 
 D  7+        1
Transcript text: Solve the following KenKen puzzle. \begin{tabular}{|l|l|l|l|l|} \hline & 1 & 2 & 3 & 4 \\ \hline A & & 4 & & 2 \\ \hline B & 3 & & 1 & \\ \hline C & 2 & $1-$ & & $1-$ \\ \hline D & $7+$ & & & 1 \\ \hline \end{tabular}
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Solution

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Solution Steps

Step 1: Analyze the Grid

The initial grid is given as follows: \[ \begin{array}{|c|c|c|c|c|} \hline & 1 & 2 & 3 & 4 \\ \hline A & 0 & 4 & 0 & 2 \\ \hline B & 3 & 0 & 1 & 0 \\ \hline C & 2 & 0 & 0 & 0 \\ \hline D & 0 & 0 & 0 & 1 \\ \hline \end{array} \] The empty cells are represented by \(0\). The constraints for the cages are:

  • Cage A: \(x_1 \cdot x_2 = 4\)
  • Cage B: \(x_3 + x_4 = 3\)
  • Cage C: \(x_5 - x_6 = 1\)
  • Cage D: \(x_7 + x_8 + x_9 = 7\)
Step 2: Fill Known Values

From the grid, we can see that:

  • Row 1 has \(4\) and \(2\) already filled.
  • Row 2 has \(3\) and \(1\) already filled.
  • Row 4 has \(1\) already filled.
Step 3: Apply Constraints

We need to ensure that the numbers \(1, 2, 3, 4\) are used without repetition in each row and column. We will start filling the empty cells while checking the constraints:

  • For Cage A, the possible pairs that multiply to \(4\) are \((1, 4)\) and \((2, 2)\), but since \(2\) is already in Row 1, we can only use \((1, 4)\).
  • For Cage B, the only possible pair that adds to \(3\) is \((2, 1)\) or \((3, 0)\), but \(1\) is already used in Row 2.
Step 4: Backtrack and Adjust

Since the initial attempts to fill the grid lead to contradictions, we need to backtrack and try different combinations. We will systematically explore all permutations of the numbers \(1, 2, 3, 4\) in the empty cells while ensuring that the constraints are satisfied.

Step 5: Check for Solutions

After testing various combinations, we find that no arrangement satisfies all the constraints simultaneously. Therefore, we conclude that there is no valid solution for the given KenKen puzzle configuration.

Final Answer

There is no valid solution for the given KenKen puzzle configuration.

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