Questions: 93 mol/L × 21 L = square mol 560.7 mol ÷ 51.0 L = square mol/L 20.94 g/mL × 80 mL

93 mol/L × 21 L = square mol
560.7 mol ÷ 51.0 L = square mol/L
20.94 g/mL × 80 mL
Transcript text: 93 . \(\frac{\mathrm{mol}}{\mathrm{~L}} \times 21 . \mathrm{L}=\square \mathrm{mol}\) \\ 560.7 \(\mathrm{~mol} \div 51.0 \mathrm{~L}=\square \frac{\mathrm{mol}}{\mathrm{~L}}\) \\ 20.94 \(\frac{\mathrm{~g}}{\mathrm{~mL}} \times 80 . \mathrm{mL}\)
failed

Solution

failed
failed

Solution Steps

Step 1: Multiplying 93 mol/L by 21 L

To multiply these two measurements, we simply multiply the numerical values and combine the units:

\[ 93 \frac{\mathrm{mol}}{\mathrm{L}} \times 21 \mathrm{L} = 93 \times 21 \, \mathrm{mol} \]

Calculating the product:

\[ 93 \times 21 = 1953 \, \mathrm{mol} \]

Since 93 has 2 significant digits and 21 has 2 significant digits, the result should be rounded to 2 significant digits:

\[ 1953 \rightarrow 2000 \, \mathrm{mol} \]

\(\boxed{2000 \, \mathrm{mol}}\)

Step 2: Dividing 560.7 mol by 51.0 L

To divide these two measurements, we simply divide the numerical values and combine the units:

\[ 560.7 \, \mathrm{mol} \div 51.0 \, \mathrm{L} = \frac{560.7}{51.0} \, \frac{\mathrm{mol}}{\mathrm{L}} \]

Calculating the quotient:

\[ \frac{560.7}{51.0} \approx 10.995 \, \frac{\mathrm{mol}}{\mathrm{L}} \]

Since 560.7 has 4 significant digits and 51.0 has 3 significant digits, the result should be rounded to 3 significant digits:

\[ 10.995 \rightarrow 11.0 \, \frac{\mathrm{mol}}{\mathrm{L}} \]

\(\boxed{11.0 \, \frac{\mathrm{mol}}{\mathrm{L}}\)

Step 3: Multiplying 20.94 g/mL by 80 mL

To multiply these two measurements, we simply multiply the numerical values and combine the units:

\[ 20.94 \frac{\mathrm{g}}{\mathrm{mL}} \times 80 \, \mathrm{mL} = 20.94 \times 80 \, \mathrm{g} \]

Calculating the product:

\[ 20.94 \times 80 = 1675.2 \, \mathrm{g} \]

Since 20.94 has 4 significant digits and 80 has 1 significant digit, the result should be rounded to 1 significant digit:

\[ 1675.2 \rightarrow 2000 \, \mathrm{g} \]

\(\boxed{2000 \, \mathrm{g}}\)

Final Answer

\[ \begin{array}{l} 93 \frac{\mathrm{mol}}{\mathrm{L}} \times 21 \mathrm{L} = \boxed{2000 \, \mathrm{mol}} \\ 560.7 \mathrm{~mol} \div 51.0 \mathrm{~L} = \boxed{11.0 \, \frac{\mathrm{mol}}{\mathrm{~L}}} \\ 20.94 \frac{\mathrm{~g}}{\mathrm{~mL}} \times 80 \mathrm{mL} = \boxed{2000 \, \mathrm{g}} \end{array} \]

Was this solution helpful?
failed
Unhelpful
failed
Helpful