Questions: Factor the polynomial.
bc-a-ba+c
bc-a-ba+c=
Transcript text: Factor the polynomial.
\[
b c-a-b a+c
\]
$\mathrm{bc}-\mathrm{a}-\mathrm{ba}+\mathrm{c}=$ $\square$
Solution
Solution Steps
To factor the given polynomial \( bc - a - ba + c \), we can look for common factors in pairs of terms and then apply the distributive property. First, group the terms as \((bc - ba) + (c - a)\). Then, factor out the common factors from each group.
Step 1: Rewrite the Polynomial
We start with the polynomial given in the problem:
\[
bc - a - ba + c
\]
This can be rearranged as:
\[
-ba + bc - a + c
\]
Step 2: Group the Terms
Next, we group the terms to facilitate factoring:
\[
(bc - ba) + (c - a)
\]
Step 3: Factor Each Group
Now, we factor out the common factors from each group:
From the first group \(bc - ba\), we can factor out \(b\):
\[
b(c - a)
\]
From the second group \(c - a\), we can factor out \(-1\):
\[
-(a - c)
\]
Step 4: Combine the Factored Groups
Combining the factored groups, we have:
\[
b(c - a) - (a - c)
\]
This can be rewritten as:
\[
-(a - c)(b + 1)
\]
Final Answer
Thus, the factored form of the polynomial \(bc - a - ba + c\) is:
\[
\boxed{-(a - c)(b + 1)}
\]