Questions: Solve the following equation. 1/(y-5)+1/20=-5/(4y-20) Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The solution set is . (Type an integer or a fraction. Use a comma to separate answers as needed.) B. The solution set is y y is a real number, y ≠ . (Type an integer or a fraction. Use a comma to separate answers as needed.) C. The solution set is ∅.

Solve the following equation.
1/(y-5)+1/20=-5/(4y-20)

Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. The solution set is  .
(Type an integer or a fraction. Use a comma to separate answers as needed.)
B. The solution set is y  y is a real number, y ≠ .
(Type an integer or a fraction. Use a comma to separate answers as needed.)
C. The solution set is ∅.
Transcript text: Solve the following equation. \[ \frac{1}{y-5}+\frac{1}{20}=\frac{-5}{4 y-20} \] Select the correct choice below and, if necessary, fill in the answer box to complete your ch A. The solution set is $\square$ \}. (Type an integer or a fraction. Use a comma to separate answers as needed.) B. The solution set is $\{y \mid y$ is a real number, $y \neq$ $\square$ \}. (Type an integer or a fraction. Use a comma to separate answers as needed.) C. The solution set is $\varnothing$.
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Solution

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Solution Steps

To solve the given equation, we need to find the value of \( y \) that satisfies the equation. Here are the high-level steps:

  1. Identify a common denominator for the fractions on both sides of the equation.
  2. Combine the fractions on the left-hand side.
  3. Simplify the equation to isolate \( y \).
  4. Solve for \( y \) and check for any restrictions or extraneous solutions.
Step 1: Identify the Equation

We start with the equation: \[ \frac{1}{y-5} + \frac{1}{20} = \frac{-5}{4y - 20} \]

Step 2: Combine Fractions

To solve the equation, we first find a common denominator for the left-hand side. The common denominator is \(20(y-5)\). Rewriting the left-hand side gives: \[ \frac{20 + (y-5)}{20(y-5)} = \frac{-5}{4y - 20} \]

Step 3: Simplify the Equation

This simplifies to: \[ \frac{y + 15}{20(y-5)} = \frac{-5}{4(y-5)} \] Cross-multiplying leads to: \[ 4(y + 15) = -100 \]

Step 4: Solve for \(y\)

Expanding and simplifying gives: \[ 4y + 60 = -100 \implies 4y = -160 \implies y = -40 \]

Final Answer

The solution set is: \[ \boxed{y = -40} \]

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