Questions: In South's CSL Championship game, Ray - South's 80.0-kg tight end - was moving with a speed of 5.58 m / s when he collided mid-air near the goal line with an opposing player. If Ray experiences a force of 920 N over a time period of 0.284 s, then determine Ray's momentum change. (No or - signs.) Momentum Change kg ⋅ m / s

In South's CSL Championship game, Ray - South's 80.0-kg tight end - was moving with a speed of 5.58 m / s when he collided mid-air near the goal line with an opposing player. If Ray experiences a force of 920 N over a time period of 0.284 s, then determine Ray's momentum change. (No or - signs.)

Momentum Change kg ⋅ m / s
Transcript text: 6. MC3Q6 Points: 0/1 In South's CSL Championship game, Ray - South's $80.0-\mathrm{kg}$ tight end - was moving with a speed of $5.58 \mathrm{~m} / \mathrm{s}$ when he collided mid-air near the goal line with an opposing player. If Ray experiences a force of 920 N over a time period of 0.284 s , then determine Ray's momentum change. ( $\mathrm{No}+\mathrm{or}-\mathrm{signs}$.) \begin{tabular}{ll|l|} Momentum Change & $\mathrm{kg} \cdot \mathrm{m} / \mathrm{s}$ \end{tabular} Info Attemnts: 2/eo Submit Help Links
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Solution

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Solution Steps

Step 1: Understand the Problem

We need to determine the change in momentum experienced by Ray during the collision. The change in momentum (\(\Delta p\)) can be calculated using the impulse-momentum theorem, which states that the impulse experienced by an object is equal to the change in its momentum.

Step 2: Use the Impulse-Momentum Theorem

The impulse-momentum theorem is given by:

\[ \Delta p = F \cdot \Delta t \]

where:

  • \( F \) is the force applied (920 N),
  • \( \Delta t \) is the time duration of the force (0.284 s).
Step 3: Calculate the Change in Momentum

Substitute the given values into the impulse-momentum theorem:

\[ \Delta p = 920 \, \text{N} \times 0.284 \, \text{s} \]

\[ \Delta p = 261.28 \, \text{kg} \cdot \text{m/s} \]

Final Answer

The change in momentum experienced by Ray is \(\boxed{261.3 \, \text{kg} \cdot \text{m/s}}\).

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