Questions: CO3^2-+H2CO3

Transcript text: CO_{3}^{2-}+H_{2}CO_{3}

Solution

Solution Steps

Step 1: Identify the Reactants and Products

First, identify the reactants and products involved in the reaction. The given species are carbonate ion (\(\mathrm{CO}_{3}^{2-}\)) and carbonic acid (\(\mathrm{H}_{2}\mathrm{CO}_{3}\)).

Step 2: Write the Unbalanced Equation

Write the unbalanced chemical equation for the reaction between carbonate ion and carbonic acid: \[ \mathrm{CO}_{3}^{2-} + \mathrm{H}_{2}\mathrm{CO}_{3} \rightarrow \text{Products} \]

Step 3: Determine the Products

In aqueous solution, carbonate ion (\(\mathrm{CO}_{3}^{2-}\)) can react with carbonic acid (\(\mathrm{H}_{2}\mathrm{CO}_{3}\)) to form bicarbonate ion (\(\mathrm{HCO}_{3}^{-}\)) and water (\(\mathrm{H}_{2}\mathrm{O}\)).

Step 4: Write the Balanced Equation

Balance the chemical equation by ensuring the number of atoms of each element and the charges are equal on both sides of the equation: \[ \mathrm{CO}_{3}^{2-} + \mathrm{H}_{2}\mathrm{CO}_{3} \rightarrow 2 \mathrm{HCO}_{3}^{-} \]

Final Answer

\[ \boxed{\mathrm{CO}_{3}^{2-} + \mathrm{H}_{2}\mathrm{CO}_{3} \rightarrow 2 \mathrm{HCO}_{3}^{-}} \]

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