Questions: The graph below is the function (f(x))
Determine which one of the following rules for continuity is violated first at (x=2).
(f(a)) is defined.
(lim x rightarrow a f(x)) exists.
(lim x rightarrow a f(x)=f(a)).
Transcript text: The graph below is the function $f(x)$
Determine which one of the following rules for continuity is violated first at $x=2$.
$f(a)$ is defined.
$\lim _{x \rightarrow a} f(x)$ exists.
$\lim _{x \rightarrow a} f(x)=f(a)$.
Solution
Solution Steps
Step 1: Check if \( f(a) \) is defined at \( x = 2 \)
To determine if \( f(2) \) is defined, we look at the value of the function at \( x = 2 \). From the graph, we see that there is a filled circle at \( (2, 3) \), indicating that \( f(2) = 3 \). Therefore, \( f(a) \) is defined at \( x = 2 \).
Step 2: Check if \( \lim_{{x \to a}} f(x) \) exists at \( x = 2 \)
To determine if the limit exists, we need to check the left-hand limit and the right-hand limit as \( x \) approaches 2. From the graph:
As \( x \) approaches 2 from the left, \( f(x) \) approaches 1.
As \( x \) approaches 2 from the right, \( f(x) \) approaches 3.
Since the left-hand limit (\( 1 \)) and the right-hand limit (\( 3 \)) are not equal, \( \lim_{{x \to 2}} f(x) \) does not exist.
Final Answer
The first rule for continuity that is violated at \( x = 2 \) is that \( \lim_{{x \to a}} f(x) \) exists.