Questions: Question 8 OMark this question Consider the equation y=15-4x. Which of the following is a graph of this equation?

Question 8
OMark this question
Consider the equation y=15-4x.

Which of the following is a graph of this equation?
Transcript text: Question 8 OMark this question Consider the equation $y=15-4 x$. Which of the following is a graph of this equation?
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Solution

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Solution Steps

To determine which graph represents the equation \( y = 15 - 4x \), we need to identify the key characteristics of the line. This equation is in the slope-intercept form \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept. Here, the slope \( m \) is \(-4\) and the y-intercept \( b \) is \(15\). The line will cross the y-axis at \( (0, 15) \) and will have a downward slope, decreasing by 4 units in \( y \) for every 1 unit increase in \( x \).

Step 1: Identify the Equation Form

The given equation is \( y = 15 - 4x \). This is in the slope-intercept form \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept.

Step 2: Determine the Slope and Y-Intercept

From the equation \( y = 15 - 4x \), we identify:

  • The slope \( m = -4 \).
  • The y-intercept \( b = 15 \).
Step 3: Analyze the Line Characteristics

The line will:

  • Cross the y-axis at the point \( (0, 15) \).
  • Have a downward slope, indicating that for every increase of 1 unit in \( x \), \( y \) decreases by 4 units.
Step 4: Plot Key Points

To further understand the line, calculate a few key points:

  • When \( x = 0 \), \( y = 15 - 4(0) = 15 \).
  • When \( x = 1 \), \( y = 15 - 4(1) = 11 \).
  • When \( x = -1 \), \( y = 15 - 4(-1) = 19 \).
Step 5: Sketch the Graph

Using the points \((0, 15)\), \((1, 11)\), and \((-1, 19)\), sketch the line. The line should pass through these points and have a negative slope.

Final Answer

The graph of the equation \( y = 15 - 4x \) is a straight line with a y-intercept at \( (0, 15) \) and a slope of \(-4\). The line decreases as \( x \) increases. The correct graph will reflect these characteristics.

\(\boxed{\text{The graph is a straight line with a negative slope and y-intercept at } (0, 15).}\)

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