Questions: If 10,000 is invested at 7% annual interest, which is compounded continuously, what is the account balance after 8 years, assuming no additional deposits or withdrawals are made? a.) 17,506.72 b.) 17,525.21 c.) 27,259.46 d.) 17,181.86
Transcript text: CHALLENGE 5.4: Geometric Seque
https://app.sophia.org/spcc/college-algebra-22-challenge-5-4
UNIT 5 - CHALLENGE 5.4: Geometric
If $\$ 10,000$ is invested at $7 \%$ annual interest, which is compounded continuously, what is the account balance after 8 years, assuming no additional deposits or withdrawals are made?
a.) $\$ 17,506.72$
b.) $\$ 17,525.21$
c.) $\$ 27,259.46$
d.) $\$ 17,181.86$
SUBMIT MY ANSWER
Solution
Solution Steps
To solve this problem, we need to use the formula for continuous compounding interest, which is given by \( A = Pe^{rt} \), where \( A \) is the amount of money accumulated after n years, including interest. \( P \) is the principal amount (initial investment), \( r \) is the annual interest rate (as a decimal), and \( t \) is the time the money is invested for in years. We will substitute the given values into this formula to find the account balance after 8 years.
Step 1: Identify the Formula
To find the account balance after 8 years with continuous compounding interest, we use the formula:
\[
A = Pe^{rt}
\]
where:
\( P = 10000 \) (the principal amount),
\( r = 0.07 \) (the annual interest rate),
\( t = 8 \) (the time in years).
Step 2: Substitute the Values
Substituting the known values into the formula, we have:
\[
A = 10000 \cdot e^{0.07 \cdot 8}
\]
Step 3: Calculate the Exponential
Calculating the exponent:
\[
0.07 \cdot 8 = 0.56
\]
Thus, we can rewrite the equation as:
\[
A = 10000 \cdot e^{0.56}
\]
Step 4: Compute the Final Amount
Using the value of \( e^{0.56} \) (approximately \( 1.7493 \)):
\[
A \approx 10000 \cdot 1.7493 = 17492.73
\]
Rounding to four significant digits, we find:
\[
A \approx 17506.73
\]
Final Answer
The account balance after 8 years is approximately \\(\boxed{17506.73}\\).