Questions: The points at -6 and -1 shown on the number line below are the real solutions to the polynomial equation x^2+7x+6=0 and represent the boundary points for the polynomial inequality x^2+7x+6>0. The points at -6 and -1 divide the number line into which three intervals?
Choose the correct answer below.
A. (-∞,-6),(-6,-1), and (-1, ∞)
B. (-∞, 1),(1,6), and (6, ∞)
C. (-∞,-1),(-1,-6), and (-6, ∞)
D. (-∞,-6],[-6,-1], and [-1, ∞)
Transcript text: The points at -6 and -1 shown on the number line below are the real solutions to the polynomial equation $\mathrm{x}^{2}+7 \mathrm{x}+6=0$ and represent the boundary points for the polynomial inequality $\mathrm{x}^{2}+7 \mathrm{x}+6>0$. The points at -6 and -1 divide the number line into which three intervals?
Choose the correct answer below.
A. $(-\infty,-6),(-6,-1)$, and $(-1, \infty)$
B. $(-\infty, 1),(1,6)$, and $(6, \infty)$
C. $(-\infty,-1),(-1,-6)$, and $(-6, \infty)$
D. $(-\infty,-6],[-6,-1]$, and $[-1, \infty)$
Solution
Solution Steps
Step 1: Identify the boundary points
The boundary points are -6 and -1.
Step 2: Determine the intervals
The boundary points divide the number line into three intervals:
From negative infinity to -6: (-∞, -6)
From -6 to -1: (-6, -1)
From -1 to positive infinity: (-1, ∞)
Final Answer:
The correct answer is A. (-∞, -6), (-6, -1), and (-1, ∞)