Questions: The points at -6 and -1 shown on the number line below are the real solutions to the polynomial equation x^2+7x+6=0 and represent the boundary points for the polynomial inequality x^2+7x+6>0. The points at -6 and -1 divide the number line into which three intervals? Choose the correct answer below. A. (-∞,-6),(-6,-1), and (-1, ∞) B. (-∞, 1),(1,6), and (6, ∞) C. (-∞,-1),(-1,-6), and (-6, ∞) D. (-∞,-6],[-6,-1], and [-1, ∞)

The points at -6 and -1 shown on the number line below are the real solutions to the polynomial equation x^2+7x+6=0 and represent the boundary points for the polynomial inequality x^2+7x+6>0. The points at -6 and -1 divide the number line into which three intervals?

Choose the correct answer below.
A. (-∞,-6),(-6,-1), and (-1, ∞)
B. (-∞, 1),(1,6), and (6, ∞)
C. (-∞,-1),(-1,-6), and (-6, ∞)
D. (-∞,-6],[-6,-1], and [-1, ∞)
Transcript text: The points at -6 and -1 shown on the number line below are the real solutions to the polynomial equation $\mathrm{x}^{2}+7 \mathrm{x}+6=0$ and represent the boundary points for the polynomial inequality $\mathrm{x}^{2}+7 \mathrm{x}+6>0$. The points at -6 and -1 divide the number line into which three intervals? Choose the correct answer below. A. $(-\infty,-6),(-6,-1)$, and $(-1, \infty)$ B. $(-\infty, 1),(1,6)$, and $(6, \infty)$ C. $(-\infty,-1),(-1,-6)$, and $(-6, \infty)$ D. $(-\infty,-6],[-6,-1]$, and $[-1, \infty)$
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Solution

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Solution Steps

Step 1: Identify the boundary points

The boundary points are -6 and -1.

Step 2: Determine the intervals

The boundary points divide the number line into three intervals:

  1. From negative infinity to -6: (-∞, -6)
  2. From -6 to -1: (-6, -1)
  3. From -1 to positive infinity: (-1, ∞)

Final Answer:

The correct answer is A. (-∞, -6), (-6, -1), and (-1, ∞)

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