Questions: q(x) = 7/(3x^3) if x < 1 -5/3 x if x > 1 Step 1 of 3: Identify the general shape and direction of the graph of this function on the interval (-∞, 1).

q(x) = 

   7/(3x^3) if x < 1
   -5/3 x if x > 1


Step 1 of 3: Identify the general shape and direction of the graph of this function on the interval (-∞, 1).
Transcript text: \[ q(x)=\left\{\begin{array}{ll} \frac{7}{3 x^{3}} & \text { if } x<1 \\ -\frac{5}{3} x & \text { if } x>1 \end{array}\right. \] Step 1 of 3 : Identify the general shape and direction of the graph of this function on the interval $(-\infty, 1)$. Answer Keypad Keyboard Shortcuts
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Solution

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Solution Steps

Step 1: Analyze the piecewise function on the given interval

We are asked to identify the shape of the graph of q(x)q(x) on the interval (,1)(-\infty, 1). On this interval, the function is defined as q(x)=73x3q(x) = \frac{7}{3x^3}.

Step 2: Determine the general shape

The function 73x3\frac{7}{3x^3} resembles the function 1x3\frac{1}{x^3}. When xx approaches 0 from the left, the function approaches -\infty. As xx goes to -\infty, the function approaches 0. The function is always negative for negative xx values.

Step 3: Match the shape with the given options

The second graph is the correct option, as it depicts a portion of a curve that is asymptotic to the y-axis as x approaches zero from the left and asymptotic to the x-axis as x approaches -\infty.

Final Answer: The second graph.

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