Questions: How many atoms of copper are in a pure copper penny that weighs 2.15 g ? (1 amu=1.6605 x 10^-24 g)
Transcript text: How many atoms of copper are in a pure copper penny that weighs 2.15 g ? $\left(1 \mathrm{amu}=1.6605 \times 10^{-24} \mathrm{~g}\right)$
Solution
Solution Steps
Step 1: Determine the Molar Mass of Copper
The molar mass of copper (Cu) is approximately \(63.55 \, \text{g/mol}\).
Step 2: Calculate the Number of Moles of Copper
Use the formula:
\[
\text{Number of moles} = \frac{\text{mass of copper}}{\text{molar mass of copper}}
\]
Substitute the given values:
\[
\text{Number of moles} = \frac{2.15 \, \text{g}}{63.55 \, \text{g/mol}}
\]
Step 3: Calculate the Number of Atoms
Use Avogadro's number, \(6.022 \times 10^{23} \, \text{atoms/mol}\), to find the number of atoms:
\[
\text{Number of atoms} = \text{Number of moles} \times 6.022 \times 10^{23} \, \text{atoms/mol}
\]