Questions: Evaluate the limit as x approaches plus or minus infinity of (3x^2 + 4x - 2) / (3x^2 - 2x + 2) and use these limits to determine the end behavior of f(x) = (3x^2 + 4x - 2) / (3x^2 - 2x + 2).
Enter the exact answers. If there is no horizontal asymptote, enter NA.
Limit as x approaches plus or minus infinity of (3x^2 + 4x - 2) / (3x^2 - 2x + 2) =
Horizontal asymptote: y =
Transcript text: Evaluate $\lim _{x \rightarrow \pm \infty} \frac{3 x^{2}+4 x-2}{3 x^{2}-2 x+2}$ and use these limits to determine the end behavior of $f(x)=\frac{3 x^{2}+4 x-2}{3 x^{2}-2 x+2}$.
Enter the exact answers. If there is no horizontal asymptote, enter NA.
\[
\lim _{x \rightarrow \pm \infty} \frac{3 x^{2}+4 x-2}{3 x^{2}-2 x+2}=
\]
Horizontal asymptote: $\boldsymbol{y}=$
Solution
Solution Steps
Step 1: Evaluate the Limit as \( x \to +\infty \)
To find \( \lim_{x \to +\infty} \frac{3x^2 + 4x - 2}{3x^2 - 2x + 2} \), we observe that both the numerator and denominator are quadratic polynomials. The leading coefficients of both polynomials are \( 3 \). Therefore, the limit is given by the ratio of the leading coefficients:
\[
\lim_{x \to +\infty} \frac{3x^2 + 4x - 2}{3x^2 - 2x + 2} = \frac{3}{3} = 1.
\]
Step 2: Evaluate the Limit as \( x \to -\infty \)
Next, we evaluate \( \lim_{x \to -\infty} \frac{3x^2 + 4x - 2}{3x^2 - 2x + 2} \). Similar to the previous limit, since both the numerator and denominator are quadratic polynomials with the same leading coefficient, we find:
\[
\lim_{x \to -\infty} \frac{3x^2 + 4x - 2}{3x^2 - 2x + 2} = \frac{3}{3} = 1.
\]
Step 3: Determine the Horizontal Asymptote
Since both limits as \( x \to +\infty \) and \( x \to -\infty \) are equal to \( 1 \), we conclude that the horizontal asymptote of the function \( f(x) = \frac{3x^2 + 4x - 2}{3x^2 - 2x + 2} \) is:
\[
y = 1.
\]