Questions: Solve the problem. You must show your work. Clearly label your answer. Use the factor theorem to decide whether x+3 is a factor of 7x^4+22x^3-3x^2+x+4.

Solve the problem. You must show your work. Clearly label your answer. Use the factor theorem to decide whether x+3 is a factor of 7x^4+22x^3-3x^2+x+4.
Transcript text: Solve the problem. You must show your work. Clearly label your answer. Use the factor theorem to decide whether $\mathrm{x}+3$ is a factor of $7 x^{4}+22 x^{3}-3 x^{2}+x+4$.
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Solution

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Solution Steps

To determine if x+3 x+3 is a factor of the polynomial 7x4+22x33x2+x+4 7x^4 + 22x^3 - 3x^2 + x + 4 , we can use the factor theorem. According to the factor theorem, x+3 x+3 is a factor of the polynomial if and only if substituting x=3 x = -3 into the polynomial results in zero. Therefore, we will evaluate the polynomial at x=3 x = -3 .

Step 1: Evaluate the Polynomial

To determine if x+3 x + 3 is a factor of the polynomial 7x4+22x33x2+x+4 7x^4 + 22x^3 - 3x^2 + x + 4 , we substitute x=3 x = -3 into the polynomial:

P(3)=7(3)4+22(3)33(3)2+(3)+4 P(-3) = 7(-3)^4 + 22(-3)^3 - 3(-3)^2 + (-3) + 4

Calculating each term:

  • 7(3)4=781=567 7(-3)^4 = 7 \cdot 81 = 567
  • 22(3)3=22(27)=594 22(-3)^3 = 22 \cdot (-27) = -594
  • 3(3)2=39=27 -3(-3)^2 = -3 \cdot 9 = -27
  • 3=3 -3 = -3
  • 4=4 4 = 4

Now, summing these results:

P(3)=567594273+4=53 P(-3) = 567 - 594 - 27 - 3 + 4 = -53

Step 2: Apply the Factor Theorem

According to the factor theorem, x+3 x + 3 is a factor of the polynomial if P(3)=0 P(-3) = 0 . Since we found that P(3)=53 P(-3) = -53 , which is not equal to zero, we conclude that x+3 x + 3 is not a factor of the polynomial.

Final Answer

Since P(3)0 P(-3) \neq 0 , we conclude that x+3 x + 3 is not a factor of 7x4+22x33x2+x+4 7x^4 + 22x^3 - 3x^2 + x + 4 . Thus, the final answer is:

Not a factor \boxed{\text{Not a factor}}

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