The probabilities are as follows:
- (a) \( P(\text{frequently or occasionally}) \approx 0.4609 \)
- (b) \( P(\text{female or not involved}) \approx 0.7606 \)
- (c) \( P(\text{male or frequently involved}) \approx 0.5897 \)
Thus, the final answers are:
\[
\boxed{P(\text{frequently or occasionally}) \approx 0.461}
\]
\[
\boxed{P(\text{female or not involved}) \approx 0.761}
\]
\[
\boxed{P(\text{male or frequently involved}) \approx 0.590}
\]