Questions: Suppose one card is drawn at random from a standard deck, Answer each part, Urite your answers as fractions. (a) Uhat is the probability that the card drawn is a face card? (b) 4 inet is the probability that the card drawn is a dimmond? (6) Yinat is thee probability that the card dravin is a face card or a diamand?

Suppose one card is drawn at random from a standard deck, Answer each part, Urite your answers as fractions.
(a) Uhat is the probability that the card drawn is a face card?
(b) 4 inet is the probability that the card drawn is a dimmond?
(6) Yinat is thee probability that the card dravin is a face card or a diamand?
Transcript text: Suppose one card is drawn at random from a standard deck, Answer each part, Urite your answers as fractions. (a) Uhat is the probability that the card drawn is a face card? (b) 4 inet is the probability that the card drawn is a dimmond? (6) Yinat is thee probability that the card dravin is a face card or a diamand?
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Solution

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Solution Steps

Step 1: Determine the total number of cards in a standard deck

A standard deck has 52 cards.

Step 2: Calculate the probability of drawing a face card

There are 12 face cards in a standard deck (3 face cards per suit: Jack, Queen, King, and there are 4 suits). The probability P(Face card) P(\text{Face card}) is: P(Face card)=1252=313. P(\text{Face card}) = \frac{12}{52} = \frac{3}{13}.

Step 3: Calculate the probability of drawing a diamond

There are 13 diamonds in a standard deck. The probability P(Diamond) P(\text{Diamond}) is: P(Diamond)=1352=14. P(\text{Diamond}) = \frac{13}{52} = \frac{1}{4}.

Step 4: Calculate the probability of drawing a face card or a diamond

To find the probability of drawing a face card or a diamond, we use the formula for the union of two events: P(Face card or Diamond)=P(Face card)+P(Diamond)P(Face card and Diamond). P(\text{Face card or Diamond}) = P(\text{Face card}) + P(\text{Diamond}) - P(\text{Face card and Diamond}). There are 3 face cards that are also diamonds (Jack, Queen, King of diamonds). Thus: P(Face card and Diamond)=352. P(\text{Face card and Diamond}) = \frac{3}{52}. Substituting the values: P(Face card or Diamond)=1252+1352352=2252=1126. P(\text{Face card or Diamond}) = \frac{12}{52} + \frac{13}{52} - \frac{3}{52} = \frac{22}{52} = \frac{11}{26}.

Final Answer

(a) The probability that the card drawn is a face card is 313\boxed{\dfrac{3}{13}}.

(b) The probability that the card drawn is a diamond is 14\boxed{\dfrac{1}{4}}.

(c) The probability that the card drawn is a face card or a diamond is 1126\boxed{\dfrac{11}{26}}.

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