A standard deck has 52 cards.
There are 12 face cards in a standard deck (3 face cards per suit: Jack, Queen, King, and there are 4 suits). The probability P(Face card) P(\text{Face card}) P(Face card) is: P(Face card)=1252=313. P(\text{Face card}) = \frac{12}{52} = \frac{3}{13}. P(Face card)=5212=133.
There are 13 diamonds in a standard deck. The probability P(Diamond) P(\text{Diamond}) P(Diamond) is: P(Diamond)=1352=14. P(\text{Diamond}) = \frac{13}{52} = \frac{1}{4}. P(Diamond)=5213=41.
To find the probability of drawing a face card or a diamond, we use the formula for the union of two events: P(Face card or Diamond)=P(Face card)+P(Diamond)−P(Face card and Diamond). P(\text{Face card or Diamond}) = P(\text{Face card}) + P(\text{Diamond}) - P(\text{Face card and Diamond}). P(Face card or Diamond)=P(Face card)+P(Diamond)−P(Face card and Diamond). There are 3 face cards that are also diamonds (Jack, Queen, King of diamonds). Thus: P(Face card and Diamond)=352. P(\text{Face card and Diamond}) = \frac{3}{52}. P(Face card and Diamond)=523. Substituting the values: P(Face card or Diamond)=1252+1352−352=2252=1126. P(\text{Face card or Diamond}) = \frac{12}{52} + \frac{13}{52} - \frac{3}{52} = \frac{22}{52} = \frac{11}{26}. P(Face card or Diamond)=5212+5213−523=5222=2611.
(a) The probability that the card drawn is a face card is 313\boxed{\dfrac{3}{13}}133.
(b) The probability that the card drawn is a diamond is 14\boxed{\dfrac{1}{4}}41.
(c) The probability that the card drawn is a face card or a diamond is 1126\boxed{\dfrac{11}{26}}2611.
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