Questions: Calculate the real power and reactive power delivered to the load shown below. Zm = (10 * -j 3.77)/(10-j 3.77) = 3.

Solution Steps

The load impedance Z_L is the series combination of the resistor and capacitor: Z_L = 10 + j3.77 Ω

The voltage source V_max = 282.8V. Assuming this is the peak voltage, the RMS voltage is V_rms = V_max/√2 = 282.8/√2 = 200V.

The current I is given by Ohm's law: I = V_rms / Z_L = 200 / (10 + j3.77) = 200∠0° / 10.69∠20.66° ≈ 18.71∠-20.66° A

The real power P is given by: P = |I|² * R = (18.71)² * 10 ≈ 3500.6 W

The reactive power Q is given by: Q = |I|² * X = (18.71)² * 3.77 ≈ 1324.7 VAR

Final Answer