To solve the given function \((f g)(x) = (\sqrt{3-x})(\sqrt{x^2-1})\), we need to:
Given the function \((f g)(x) = (\sqrt{3-x})(\sqrt{x^2-1})\), we need to evaluate it for a specific value of \(x\).
We substitute \(x = 2\) into the function: \[ (f g)(2) = (\sqrt{3-2})(\sqrt{2^2-1}) \]
Simplify the terms inside the square roots: \[ \sqrt{3-2} = \sqrt{1} = 1 \] \[ \sqrt{2^2-1} = \sqrt{4-1} = \sqrt{3} \]
Multiply the simplified terms: \[ (f g)(2) = 1 \cdot \sqrt{3} = \sqrt{3} \]
The numerical value of \(\sqrt{3}\) is approximately \(1.7321\).
\[ \boxed{(f g)(2) = 1.7321} \]
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