The given function is \( h(x) = \frac{1}{x + 8} \). It needs to be expressed in the form \( f(g(x)) \), where \( g(x) = x + 8 \).
We are given \( g(x) = x + 8 \).
Since \( g(x) = x + 8 \), we can substitute \( g(x) \) into \( h(x) \): \[ h(x) = \frac{1}{x + 8} = \frac{1}{g(x)} \]
From the expression \( h(x) = \frac{1}{g(x)} \), we can see that \( f(x) = \frac{1}{x} \).
\[ f(x) = \frac{1}{x} \]
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