Questions: Law of sine
5) m angle C=18°, b=26 ft, c=11 ft
6) m angle C=88°, m angle A=65°, c=11 yd
7) m angle A=116°, c=12 ft, a=35 ft
8) m angle A=31°, c=29 in, a=28 in
9) m angle B=34°, b=33 cm, a=24 cm
10) m angle B=157°, a=22 ft, b=7 ft
Transcript text: Law of sine
5) $m \angle C=18^{\circ}, b=26 \mathrm{ft}, c=11 \mathrm{ft}$
6) $m \angle C=88^{\circ}, m \angle A=65^{\circ}, c=11 \mathrm{yd}$
7) $m \angle A=116^{\circ}, c=12 \mathrm{ft}, a=35 \mathrm{ft}$
8) $m \angle A=31^{\circ}, c=29$ in, $a=28$ in
9) $m \angle B=34^{\circ}, b=33 \mathrm{~cm}, a=24 \mathrm{~cm}$
10) $m \angle B=157^{\circ}, a=22 \mathrm{ft}, b=7 \mathrm{ft}$
Solution
Solution Steps
Step 1: Use the Law of Sines for Question 5
Given:
\( m \angle C = 18^\circ \)
\( b = 26 \, \text{ft} \)
\( c = 11 \, \text{ft} \)
The Law of Sines states:
\[
\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}
\]
For this problem, we use:
\[
\frac{b}{\sin B} = \frac{c}{\sin C}
\]
Substitute the known values:
\[
\frac{26}{\sin B} = \frac{11}{\sin 18^\circ}
\]
Solve for \(\sin B\):
\[
\sin B = \frac{26 \cdot \sin 18^\circ}{11}
\]
Step 2: Use the Law of Sines for Question 6
Given:
\( m \angle C = 88^\circ \)
\( m \angle A = 65^\circ \)
\( c = 11 \, \text{yd} \)
First, find \( m \angle B \):
\[
m \angle B = 180^\circ - m \angle A - m \angle C = 180^\circ - 65^\circ - 88^\circ
\]
Use the Law of Sines:
\[
\frac{a}{\sin A} = \frac{c}{\sin C}
\]
Substitute the known values:
\[
\frac{a}{\sin 65^\circ} = \frac{11}{\sin 88^\circ}
\]
Solve for \( a \):
\[
a = \frac{11 \cdot \sin 65^\circ}{\sin 88^\circ}
\]
Step 3: Use the Law of Sines for Question 7
Given:
\( m \angle A = 116^\circ \)
\( c = 12 \, \text{ft} \)
\( a = 35 \, \text{ft} \)
First, find \( m \angle C \) using the Law of Sines:
\[
\frac{a}{\sin A} = \frac{c}{\sin C}
\]
Substitute the known values:
\[
\frac{35}{\sin 116^\circ} = \frac{12}{\sin C}
\]
Solve for \(\sin C\):
\[
\sin C = \frac{12 \cdot \sin 116^\circ}{35}
\]
Find \( m \angle C \) using the inverse sine function.
Final Answer
For question 5: \( \boxed{\sin B = \frac{26 \cdot \sin 18^\circ}{11}} \)