First, we need to factor the number 28 into its prime factors. The prime factorization of 28 is:
\[ 28 = 2^2 \times 7 \]
Using the property of square roots, \(\sqrt{a \times b} = \sqrt{a} \times \sqrt{b}\), we can simplify \(\sqrt{28}\) as follows:
\[ \sqrt{28} = \sqrt{2^2 \times 7} = \sqrt{2^2} \times \sqrt{7} \]
Since \(\sqrt{2^2} = 2\), we have:
\[ \sqrt{28} = 2 \times \sqrt{7} \]
The simplified form of \(\sqrt{28}\) is:
\[ \boxed{2 \sqrt{7}} \]
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