Questions: Calculate the volume occupied by 0.627 mol of nitrogen gas at a pressure of 1.06 atm and a temperature of 287 K .

Calculate the volume occupied by 0.627 mol of nitrogen gas at a pressure of 1.06 atm and a temperature of 287 K .
Transcript text: Calculate the volume occupied by 0.627 mol of nitrogen gas at a pressure of 1.06 atm and a temperature of 287 K .
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Solution

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Solution Steps

Step 1: Identify the Ideal Gas Law

The Ideal Gas Law is given by the equation: \[ PV = nRT \] where:

  • \( P \) is the pressure,
  • \( V \) is the volume,
  • \( n \) is the number of moles,
  • \( R \) is the ideal gas constant,
  • \( T \) is the temperature in Kelvin.
Step 2: Assign Given Values

From the problem, we have:

  • \( n = 0.627 \) mol,
  • \( P = 1.06 \) atm,
  • \( T = 287 \) K.

The ideal gas constant \( R \) is \( 0.0821 \) L·atm/(mol·K).

Step 3: Rearrange the Ideal Gas Law to Solve for Volume

Rearrange the equation to solve for \( V \): \[ V = \frac{nRT}{P} \]

Step 4: Substitute the Given Values into the Equation

Substitute the values into the equation: \[ V = \frac{(0.627 \, \text{mol}) (0.0821 \, \text{L·atm/(mol·K)}) (287 \, \text{K})}{1.06 \, \text{atm}} \]

Step 5: Calculate the Volume

Perform the calculation: \[ V = \frac{(0.627) (0.0821) (287)}{1.06} \] \[ V = \frac{14.7357}{1.06} \] \[ V \approx 13.9007 \, \text{L} \]

Final Answer

The volume occupied by 0.627 mol of nitrogen gas at a pressure of 1.06 atm and a temperature of 287 K is: \[ \boxed{13.9007 \, \text{L}} \]

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