Questions: Fourteen gallons of a salt solution consists of 35% salt. It is the result of mixing a 65% solution with a 30% solution. How many gallons of each of the solutions was used? Let x= the number of gallons of the 65% solution and y= the number of gallons of the 30% solution. The corresponding modeling system is x+y=14, 0.65x+0.3y=0.35(14). Solve the system by using the method of substitution.

Fourteen gallons of a salt solution consists of 35% salt. It is the result of mixing a 65% solution with a 30% solution. How many gallons of each of the solutions was used? Let x= the number of gallons of the 65% solution and y= the number of gallons of the 30% solution. The corresponding modeling system is x+y=14, 0.65x+0.3y=0.35(14). Solve the system by using the method of substitution.
Transcript text: Question 8 of 10, Step 1 of 1 Correct Fourteen gallons of a salt solution consists of $35 \%$ salt. It is the result of mixing a $65 \%$ solution with a $30 \%$ solution. How many gallons of each of the solutions was used? Let $x=$ the number of gallons of the $65 \%$ solution and $y=$ the number of gallons of the $30 \%$ solution. The corresponding modeling system is $\left\{\begin{array}{l}x+y=14 \\ 0.65 x+0.3 y=0.35(14)\end{array}\right.$. Solve the system by using the method of substitution.
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Solution

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Solution Steps

To solve the system of equations using the method of substitution, follow these steps:

  1. Solve the first equation x+y=14x + y = 14 for one of the variables, say yy.
  2. Substitute the expression for yy into the second equation 0.65x+0.3y=0.35×140.65x + 0.3y = 0.35 \times 14.
  3. Solve the resulting equation for xx.
  4. Substitute the value of xx back into the expression for yy to find yy.
Step 1: Set Up the Equations

We start with the system of equations based on the problem statement: \[ \begin{align*}

  1. & \quad x + y = 14 \quad \text{(1)} \\
  2. & \quad 0.65x + 0.3y = 0.35 \times 14 \quad \text{(2)} \end{align*} \] Calculating 0.35×140.35 \times 14 gives us 4.94.9, so equation (2) can be rewritten as: 0.65x+0.3y=4.9 0.65x + 0.3y = 4.9
Step 2: Solve for One Variable

From equation (1), we can express yy in terms of xx: y=14x(3) y = 14 - x \quad \text{(3)}

Step 3: Substitute and Solve

Substituting equation (3) into equation (2): 0.65x+0.3(14x)=4.9 0.65x + 0.3(14 - x) = 4.9 Expanding this gives: 0.65x+4.20.3x=4.9 0.65x + 4.2 - 0.3x = 4.9 Combining like terms results in: 0.35x+4.2=4.9 0.35x + 4.2 = 4.9 Subtracting 4.24.2 from both sides: 0.35x=0.7 0.35x = 0.7 Dividing by 0.350.35: x=2 x = 2

Step 4: Find the Other Variable

Now substituting x=2x = 2 back into equation (3) to find yy: y=142=12 y = 14 - 2 = 12

Final Answer

The number of gallons of the 65%65\% solution is 22 and the number of gallons of the 30%30\% solution is 1212. Thus, the final answer is: (x=2,y=12) \boxed{(x = 2, y = 12)}

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