First, we need to determine the number of valence electrons for each atom in the compound HOCl.
Next, we sum the valence electrons for all the atoms in the compound.
1 (H)+6 (O)+7 (Cl)=14 valence electrons 1 \, (\text{H}) + 6 \, (\text{O}) + 7 \, (\text{Cl}) = 14 \, \text{valence electrons} 1(H)+6(O)+7(Cl)=14valence electrons
14\boxed{14}14
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