We are given that ∠DEG ≅ ∠FEG and EG ⊥ DF.
EG ⊥ DF implies that angles ∠DGE and ∠FGE are right angles, and therefore congruent.
Side EG is common to both triangles ΔDEG and ΔFEG.
Since ∠DEG ≅ ∠FEG, EG is a shared side, and ∠DGE ≅ ∠FGE, by the Angle-Side-Angle postulate, triangles ΔDEG and ΔFEG are congruent.
Since triangles ΔDEG and ΔFEG are congruent, their corresponding sides must also be congruent. This implies that DG ≅ FG.
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