Questions: If (f(x)=frac7-x^23+x^2), find:
[
f^prime(x)=
]
Transcript text: If $f(x)=\frac{7-x^{2}}{3+x^{2}}$, find:
\[
f^{\prime}(x)=
\]
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Solution
Solution Steps
Step 1: Identify the function and its components
To find the derivative of the function \(f(x) = \frac{7 - x^2}{3 + x^2}\), we identify \(u(x) = 7 - x^2\) and \(v(x) = 3 + x^2\).
Step 2: Apply the quotient rule
The quotient rule for differentiation is given by \(g'(x) = \frac{{u'(x)v(x) - u(x)v'(x)}}{{[v(x)]^2}}\).
Here, \(u'(x) = -2x\) and \(v'(x) = 2x\). Substituting these into the quotient rule gives:
\(f'(x) = \frac{(-2x)(3 + x^2) - (7 - x^2)(2x)}{(3 + x^2)^2}\).
Step 3: Simplify the expression
Simplifying the expression, we get:
\(f'(x) = \frac{-2x(3 + 7)}{(3 + x^2)^2}\).
Final Answer:
The derivative of the function at \(x = 1\) is \(f'(x) = -1.25\).