Questions: Draw the Lewis dot diagram for a K− anion.

Transcript text: Draw the Lewis dot diagram for a $\mathrm{K}^{-}$anion.

Solution

Solution Steps

Step 1: Identify the Element and its Electron Configuration

Potassium (K) is the element in question. The atomic number of potassium is 19, which means it has 19 electrons in its neutral state. The electron configuration for neutral potassium is: \[ \text{K: } 1s^2 2s^2 2p^6 3s^2 3p^6 4s^1 \]

Step 2: Determine the Electron Configuration for the Anion

A $\mathrm{K}^{-}$ anion means potassium has gained one extra electron, making the total number of electrons 20. The electron configuration for $\mathrm{K}^{-}$ is: \[ \mathrm{K}^{-}: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 \]

Step 3: Draw the Lewis Dot Diagram

The Lewis dot diagram represents the valence electrons around the element. For $\mathrm{K}^{-}$, the valence shell is the 4s orbital, which now contains 2 electrons.

Final Answer

\[ \boxed{\text{K}^{-} \text{ with 2 dots around it}} \]

The Lewis dot diagram for $\mathrm{K}^{-}$ is: \[ \begin{array}{c} \text{K}^{-} \\ \cdot \quad \cdot \end{array} \]

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