Questions: Radicals and Quadratic Functions
Table for a square root function
Fill in the table using this function rule.
f(x) = sqrt(3-x)
Simplify your answers as much as possible. Click "Not a real number" if applicable.
x f(x)
-22
3
7
Transcript text: Radicals and Quadratic Functions
Table for a square root function
Fill in the table using this function rule.
\[
f(x)=\sqrt{3-x}
\]
Simplify your answers as much as possible. Click "Not a real number" if applicable.
\begin{tabular}{|c|c|}
\hline$x$ & $f(x)$ \\
\hline-22 & $\square$ \\
\hline 3 & $\square$ \\
\hline 7 & $\square$ \\
\hline
\end{tabular}
Solution
Solution Steps
Step 1: Evaluate \( f(-22) \)
Substitute \( x = -22 \) into the function \( f(x) = \sqrt{3 - x} \):
\[
f(-22) = \sqrt{3 - (-22)} = \sqrt{3 + 22} = \sqrt{25}
\]
\[
\sqrt{25} = 5
\]
Thus, \( f(-22) = 5 \).
Step 2: Evaluate \( f(3) \)
Substitute \( x = 3 \) into the function \( f(x) = \sqrt{3 - x} \):
\[
f(3) = \sqrt{3 - 3} = \sqrt{0}
\]
\[
\sqrt{0} = 0
\]
Thus, \( f(3) = 0 \).
Step 3: Evaluate \( f(7) \)
Substitute \( x = 7 \) into the function \( f(x) = \sqrt{3 - x} \):
\[
f(7) = \sqrt{3 - 7} = \sqrt{-4}
\]
Since the square root of a negative number is not a real number, \( f(7) \) is not a real number.
Final Answer
The completed table is:
\[
\begin{tabular}{|c|c|}
\hline
x & f(x) \\
\hline
-22 & \boxed{5} \\
\hline
3 & \boxed{0} \\
\hline
7 & \text{Not a real number} \\
\hline
\end{tabular}
\]