Questions: Find the intervals on which f(x) is increasing, the intervals on which f(x) is decreasing, and the local extrema, f(x)=x^3+5x-14 Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The function is increasing on . (Type your answer using interval notation. Type integers or simplified fractions. Use a comma to separate answers as needed.) B. The function is never increasing. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The function is decreasing on . (Type your answer using interval notation. Type integers or simplified fractions. Use a comma to separate answers as needed.) B. The function is never decreasing. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. (Type integers or simplified fractions. Use a comma to separate answers as needed.) A. The function has local maxima f(c)= and local minima f(c)= . B. The function has local minima f(c)= , and no local maxima.

Find the intervals on which f(x) is increasing, the intervals on which f(x) is decreasing, and the local extrema,
f(x)=x^3+5x-14

Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. The function is increasing on .
(Type your answer using interval notation. Type integers or simplified fractions. Use a comma to separate answers as needed.)
B. The function is never increasing.

Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. The function is decreasing on .
(Type your answer using interval notation. Type integers or simplified fractions. Use a comma to separate answers as needed.)
B. The function is never decreasing.

Select the correct choice below and, if necessary, fill in the answer box to complete your choice. (Type integers or simplified fractions. Use a comma to separate answers as needed.)
A. The function has local maxima f(c)= and local minima f(c)= .
B. The function has local minima f(c)= , and no local maxima.
Transcript text: Find the intervals on which $f(x)$ is increasing, the intervals on which $f(x)$ is decreasing, and the local extrema, \[ f(x)=x^{3}+5 x-14 \] Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The function is increasing on $\square$ . (Type your answer using interval notation. Type integers or simplified fractions. Use a comma to separate answers as needed.) B. The function is never increasing. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The function is decreasing on $\square$ . (Type your answer using interval notation. Type integers or simplified fractions. Use a comma to separate answers as needed.) B. The function is never decreasing. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. (Type integers or simplified fractions. Use a comma to separate answers as needed.) A. The function has local maxima $f(c)=$ $\square$ and local minima $f(c)=$ $\square$ . B. The function has local minima $f(c)=$ $\square$ , and no local maxima.
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Solution

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Solution Steps

Step 1: Find the Derivative

To determine the intervals on which the function is increasing or decreasing, we first need to find the derivative of the function \( f(x) = x^3 + 5x - 14 \).

\[ f'(x) = \frac{d}{dx}(x^3 + 5x - 14) = 3x^2 + 5 \]

Step 2: Find Critical Points

The critical points occur where the derivative is zero or undefined. Since \( f'(x) = 3x^2 + 5 \) is a polynomial, it is defined everywhere. We set the derivative equal to zero to find the critical points:

\[ 3x^2 + 5 = 0 \]

Solving for \( x \), we get:

\[ 3x^2 = -5 \quad \Rightarrow \quad x^2 = -\frac{5}{3} \]

Since \( x^2 = -\frac{5}{3} \) has no real solutions, there are no critical points.

Step 3: Determine Intervals of Increase and Decrease

Since there are no critical points, the sign of the derivative \( f'(x) = 3x^2 + 5 \) will determine the behavior of the function. Notice that \( 3x^2 + 5 > 0 \) for all real \( x \) because \( 3x^2 \geq 0 \) and adding 5 makes it positive.

Thus, the function is increasing on the entire real line.

Step 4: Determine Local Extrema

Since the function is increasing everywhere and there are no critical points, there are no local maxima or minima.

Final Answer

  • The function is increasing on \(\boxed{(-\infty, \infty)}\).
  • The function is never decreasing.
  • The function has no local maxima or minima.
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