Questions: Given the function f(x)=6x+8, evaluate and simplify the expressions below.
f(a)=
f(a+h)=
(f(a+h)-f(a))/h=
Transcript text: Given the function $f(x)=6 x+8$, evaluate and simplify the expressions below.
\[
f(a)=
\]
\[
f(a+h)=
\]
\[
\frac{f(a+h)-f(a)}{h}=
\]
Solution
Solution Steps
To solve the given problem, we need to evaluate the function \( f(x) = 6x + 8 \) at different points and simplify the resulting expressions.
Evaluate \( f(a) \) by substituting \( a \) into the function.
Evaluate \( f(a+h) \) by substituting \( a+h \) into the function.
Compute the difference quotient \( \frac{f(a+h) - f(a)}{h} \) and simplify.
Step 1: Evaluate \( f(a) \)
To find \( f(a) \), we substitute \( a = 5 \) into the function \( f(x) = 6x + 8 \):
\[
f(a) = 6(5) + 8 = 30 + 8 = 38
\]
Step 2: Evaluate \( f(a+h) \)
To find \( f(a+h) \), we substitute \( a = 5 \) and \( h = 2 \) into the function \( f(x) = 6x + 8 \):
\[
f(a+h) = f(5+2) = f(7) = 6(7) + 8 = 42 + 8 = 50
\]
Step 3: Compute the Difference Quotient
To find the difference quotient \( \frac{f(a+h) - f(a)}{h} \), we use the values obtained in the previous steps:
\[
\frac{f(a+h) - f(a)}{h} = \frac{50 - 38}{2} = \frac{12}{2} = 6.0
\]