First, we need to convert the frequency from millihertz (mHz) to hertz (Hz). Given that \(1000 \, \text{mHz} = 1 \, \text{Hz}\):
\[ 60 \, \text{mHz} = \frac{60}{1000} \, \text{Hz} = 0.060 \, \text{Hz} \]
The relationship between the speed of a wave (\(v\)), its frequency (\(f\)), and its wavelength (\(\lambda\)) is given by the formula:
\[ v = f \lambda \]
Rearrange the formula to solve for the wavelength (\(\lambda\)):
\[ \lambda = \frac{v}{f} \]
Substitute the given values (\(v = 400 \, \text{m/s}\) and \(f = 0.060 \, \text{Hz}\)):
\[ \lambda = \frac{400 \, \text{m/s}}{0.060 \, \text{Hz}} = \frac{400}{0.060} \, \text{m} = 6666.6667 \, \text{m} \]
\(\boxed{\lambda = 6666.6667 \, \text{m}}\)
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