To solve these problems, we can use the principle of inclusion-exclusion and basic set operations.
(a) To find how many people carried a cell phone or a tablet, we use the formula for the union of two sets: |A ∪ B| = |A| + |B| - |A ∩ B|, where |A| is the number of people with a cell phone, |B| is the number with a tablet, and |A ∩ B| is the number with both.
(b) To find how many people carried neither a cell phone nor a tablet, we subtract the number of people who carried either from the total number of people surveyed.
(c) To find how many people carried a cell phone only, we subtract the number of people who carried both from the number of people who carried a cell phone.
To find the number of people who carried either a cell phone or a tablet, we use the principle of inclusion-exclusion. The formula is:
\[
|A \cup B| = |A| + |B| - |A \cap B|
\]
where:
- \(|A|\) is the number of people with a cell phone, which is 46.
- \(|B|\) is the number of people with a tablet, which is 64.
- \(|A \cap B|\) is the number of people with both, which is 1.
Substituting the values, we get:
\[
|A \cup B| = 46 + 64 - 1 = 109
\]
To find the number of people who carried neither a cell phone nor a tablet, we subtract the number of people who carried either from the total number of people surveyed:
\[
\text{Neither} = \text{Total} - |A \cup B| = 134 - 109 = 25
\]
To find the number of people who carried only a cell phone, we subtract the number of people who carried both from the number of people who carried a cell phone:
\[
\text{Cell Phone Only} = |A| - |A \cap B| = 46 - 1 = 45
\]
- (a) The number of people who carried a cell phone or a tablet is \(\boxed{109}\).
- (b) The number of people who carried neither a cell phone nor a tablet is \(\boxed{25}\).
- (c) The number of people who carried a cell phone only is \(\boxed{45}\).