Questions: The program should output even values between -10 and 10 (inclusive), so -10 -8 ... 8 10 . What should XXX be? i=-10 ; i<=10 ; i=i+2

The answer is the third one (or C): i=-10 ; i<=10 ; i=i+2

Explanation for each option:

1. Option 1: i=-10 ;(i * 2)<=10,++i

   • This option is incorrect because the condition (i * 2) <= 10 does not correctly iterate through the even numbers between -10 and 10. Additionally, the increment operation ++i increases i by 1, which would not produce the correct sequence of even numbers.

2. Option 2: i=-10 ; i<10 ; i=i+2

   • This option is incorrect because the condition i < 10 will stop the loop before reaching 10. Therefore, the number 10 will not be included in the output.

3. Option 3: i=-10 ; i<=10 ; i=i+2

   • This option is correct because it initializes i to -10, and the condition i <= 10 ensures that the loop runs until i is 10, inclusive. The increment i=i+2 ensures that only even numbers are printed.

4. Option 4: i=-10 ;(i * 2)<10 ;++i

   • This option is incorrect because the condition (i * 2) < 10 does not correctly iterate through the even numbers between -10 and 10. Additionally, the increment operation ++i increases i by 1, which would not produce the correct sequence of even numbers.

Summary: The correct loop to output even values between -10 and 10 (inclusive) is i=-10 ; i<=10 ; i=i+2. This ensures that the loop starts at -10, includes 10, and increments by 2 to cover all even numbers in the specified range.