Questions: Dice Rolls: You roll a pair of fair 6 -sided dice. Use the information below to answer the questions. a) First let's complete the sample space. The sample space is the set of all possible outcomes from a probability experiment. Therefore, we want to list all the outcomes if you roll a pair of fair 6 -sided dice. If you roll a 2 on the first die and a 4 on the second die then the entry will be 2,4. Fill in the blanks following this pattern (Hint: do not put any spaces in the blanks). 2nd roll=1 2nd roll=2 2nd roll=3 2nd roll=4 2nd roll=5 2nd roll=6 1st roll=1 1,1 1,2 1,3 1,4 1,5 1,6 1st roll=2 2,1 2,2 2,4 2,5 2,6 1st roll=3 3,2 3,3 3,4 3,5 3,6 1st roll=4 4,1 4,2 4,4 4,5 4,6 1st roll=5 5,1 5,2 5,3 5,4 5,5 5,6 1st roll=6 6,1 6,3 6,4 6,5 b) When you roll both dice and add up the pips (pips are the dots on the dice), what's the probability of getting a sum of 1 ? (round to 4 decimal places, if necessary) c) When you roll both dice and add up the pips, what's the probability of getting a sum of 5 ? (round to 4 decimal places, if necessary) d) When you roll both dice and add up the pips, what's the probability of getting a sum of 12? (round to 4 decimal places, if necessary)

Dice Rolls: You roll a pair of fair 6 -sided dice. Use the information below to answer the questions.
a) First let's complete the sample space. The sample space is the set of all possible outcomes from a probability experiment. Therefore, we want to list all the outcomes if you roll a pair of fair 6 -sided dice. If you roll a 2 on the first die and a 4 on the second die then the entry will be 2,4. Fill in the blanks following this pattern (Hint: do not put any spaces in the blanks).

  2nd roll=1  2nd roll=2  2nd roll=3  2nd roll=4  2nd roll=5  2nd roll=6 
 1st roll=1  1,1  1,2  1,3  1,4  1,5  1,6 
 1st roll=2  2,1  2,2    2,4  2,5  2,6 
 1st roll=3    3,2  3,3  3,4  3,5  3,6 
 1st roll=4  4,1  4,2    4,4  4,5  4,6 
 1st roll=5  5,1  5,2  5,3  5,4  5,5  5,6 
 1st roll=6  6,1    6,3  6,4  6,5   

b) When you roll both dice and add up the pips (pips are the dots on the dice), what's the probability of getting a sum of 1 ? (round to 4 decimal places, if necessary)

c) When you roll both dice and add up the pips, what's the probability of getting a sum of 5 ? (round to 4 decimal places, if necessary)

d) When you roll both dice and add up the pips, what's the probability of getting a sum of 12? (round to 4 decimal places, if necessary)
Transcript text: Dice Rolls: You roll a pair of fair 6 -sided dice. Use the information below to answer the questions. a) First let's complete the sample space. The sample space is the set of all possible outcomes from a probability experiment. Therefore, we want to list all the outcomes if you roll a pair of fair 6 -sided dice. If you roll a 2 on the first die and a 4 on the second die then the entry will be 2,4. Fill in the blanks following thispattern (Hint: do not put any spaces in the blanks). \begin{tabular}{|l|r|r|r|r|r|r|} \hline & 2nd roll=1 & 2nd roll=2 & 2nd roll=3 & 2nd roll=4 & 2nd roll=5 & 2nd roll=6 \\ \hline 1st roll=1 & 1,1 & 1,2 & 1,3 & 1,4 & 1,5 & 1,6 \\ \hline 1st roll=2 & 2,1 & 2,2 & $\square$ & 2,4 & 2,5 & 2,6 \\ \hline 1st roll=3 & & 3,2 & 3,3 & 3,4 & 3,5 & 3,6 \\ \hline 1st roll=4 & 4,1 & 4,2 & $\square$ & 4,4 & 4,5 & 4,6 \\ \hline 1st roll=5 & 5,1 & 5,2 & 5,3 & 5,4 & 5,5 & 5,6 \\ \hline 1st roll=6 & 6,1 & $\square$ & 6,3 & 6,4 & 6,5 & $\square$ \\ \hline \end{tabular} b) When you roll both dice and add up the pips (pips are the dots on the dice), what's the probability of getting a sum of 1 ? (round to 4 decimal places, if necessary) $\square$ c) When you roll both dice and add up the pips, what's the probability of getting a sum of 5 ? (round to 4 decimal places, if necessary) $\square$ d) When you roll both dice and add up the pips, what's the probability of getting a sum of 12? (round to 4 decimal places, if necessary) $\square$
failed

Solution

failed
failed

Solution Steps

To solve the given problems, we need to follow these steps:

a) Complete the sample space by listing all possible outcomes of rolling two 6-sided dice. b) Calculate the probability of getting a sum of 1 when rolling two dice. c) Calculate the probability of getting a sum of 5 when rolling two dice. d) Calculate the probability of getting a sum of 12 when rolling two dice.

Solution Approach
  1. Generate all possible outcomes of rolling two 6-sided dice.
  2. Count the number of outcomes that result in the desired sum.
  3. Calculate the probability by dividing the number of favorable outcomes by the total number of possible outcomes.
Step 1: Sample Space

The sample space for rolling two 6-sided dice consists of all possible ordered pairs \((i, j)\) where \(i\) and \(j\) can take values from 1 to 6. The complete sample space is given by: \[ \text{sample\_space} = \{(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)\} \] This results in a total of \(36\) possible outcomes.

Step 2: Probability of Sum of 1

To find the probability of obtaining a sum of \(1\), we note that there are no outcomes in the sample space that yield this sum. Therefore, the number of favorable outcomes is \(0\): \[ \text{sum\_1} = \{\} \quad \Rightarrow \quad P(\text{sum} = 1) = \frac{0}{36} = 0.0 \]

Step 3: Probability of Sum of 5

Next, we calculate the probability of obtaining a sum of \(5\). The favorable outcomes that yield this sum are: \[ \text{sum\_5} = \{(1, 4), (2, 3), (3, 2), (4, 1)\} \] There are \(4\) favorable outcomes, so the probability is: \[ P(\text{sum} = 5) = \frac{4}{36} = \frac{1}{9} \approx 0.1111 \]

Step 4: Probability of Sum of 12

Finally, we find the probability of obtaining a sum of \(12\). The only favorable outcome for this sum is: \[ \text{sum\_12} = \{(6, 6)\} \] There is \(1\) favorable outcome, thus the probability is: \[ P(\text{sum} = 12) = \frac{1}{36} \approx 0.0278 \]

Final Answer

The probabilities for the respective sums are:

  • Probability of getting a sum of \(1\): \(0.0000\)
  • Probability of getting a sum of \(5\): \(0.1111\)
  • Probability of getting a sum of \(12\): \(0.0278\)

Thus, the final answers are: \[ \boxed{P(\text{sum} = 1) = 0.0000, \quad P(\text{sum} = 5) = 0.1111, \quad P(\text{sum} = 12) = 0.0278} \]

Was this solution helpful?
failed
Unhelpful
failed
Helpful