Questions: Chapter 1 Section 5 - Homework Name Date Due Period 14. In angle ABC, vector BX is in the interior of the angle, m angle ABX is 12 more than 4 times m angle CBX, and m angle ABC=92°. a. Draw a diagram to represent the situation

Chapter 1 Section 5 - Homework
Name  
Date Due   Period  
14. In angle ABC, vector BX is in the interior of the angle, m angle ABX is 12 more than 4 times m angle CBX, and m angle ABC=92°.
a. Draw a diagram to represent the situation
Transcript text: Chapter 1 Section 5 - Homework Name $\qquad$ Date Due $\qquad$ Period $\qquad$ 14. In $\angle A B C, \overrightarrow{B X}$ is in the interior of the angle, $m \angle A B X$ is 12 more than 4 times $m \angle C B X$, and $m \angle A B C=92^{\circ}$. a. Draw a diagram to represent the situation
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Solution

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To address the problem, let's break down the information given and create a diagram based on it.

  1. Understanding the Problem:

    • We have an angle, \(\angle ABC\), with a measure of \(92^\circ\).
    • A ray, \(\overrightarrow{BX}\), is inside \(\angle ABC\).
    • The measure of \(\angle ABX\) is 12 more than 4 times the measure of \(\angle CBX\).
  2. Setting Up the Equations:

    • Let \(m \angle CBX = x\).
    • Then, \(m \angle ABX = 4x + 12\).
    • Since \(\overrightarrow{BX}\) is inside \(\angle ABC\), the sum of \(m \angle ABX\) and \(m \angle CBX\) should equal \(m \angle ABC\).
    • Therefore, the equation is: \[ (4x + 12) + x = 92 \]
  3. Solving the Equation:

    • Combine like terms: \[ 5x + 12 = 92 \]
    • Subtract 12 from both sides: \[ 5x = 80 \]
    • Divide by 5: \[ x = 16 \]
    • So, \(m \angle CBX = 16^\circ\) and \(m \angle ABX = 4(16) + 12 = 64 + 12 = 76^\circ\).
  4. Drawing the Diagram:

    • Draw a horizontal line and label it as \(\overrightarrow{BC}\).
    • At point \(B\), draw another line to the left, labeling it as \(\overrightarrow{BA}\).
    • The angle between \(\overrightarrow{BA}\) and \(\overrightarrow{BC}\) is \(\angle ABC = 92^\circ\).
    • Inside \(\angle ABC\), draw a ray \(\overrightarrow{BX}\) such that it divides \(\angle ABC\) into two angles: \(\angle ABX = 76^\circ\) and \(\angle CBX = 16^\circ\).

This diagram visually represents the situation described in the problem, with the correct angle measures calculated.

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