Questions: Evaluate the limit as x approaches 0 from the left of e^(2 / x). If we let t = 2/x, we know that t approaches negative infinity as x approaches 0 from the left. Therefore, by the limit as x approaches negative infinity of e^x = 0, the limit as x approaches 0 from the left of e^(2 / x) = the limit as t approaches negative infinity of e^t = 0

Evaluate the limit as x approaches 0 from the left of e^(2 / x).

If we let t = 2/x, we know that t approaches negative infinity as x approaches 0 from the left. Therefore, by the limit as x approaches negative infinity of e^x = 0,

the limit as x approaches 0 from the left of e^(2 / x) = the limit as t approaches negative infinity of e^t = 0
Transcript text: Evaluate $\lim _{x \rightarrow 0^{-}} e^{2 / x}$ If we let $t=\frac{2}{x}$, we know that $t \rightarrow-\infty$ as $x \rightarrow 0^{-}$. Therefore, by $\lim _{x \rightarrow-\infty} e^{x}=0$, \[ \lim _{x \rightarrow 0^{-}} e^{2 / x}=\lim _{t \rightarrow-\infty} e^{t}=\square \]
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Solution

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Solution Steps

Step 1: Substitute the variable

Let \( t = \frac{2}{x} \). As \( x \rightarrow 0^{-} \), \( t \rightarrow -\infty \).

Step 2: Rewrite the limit

The original limit \( \lim _{x \rightarrow 0^{-}} e^{2 / x} \) can be rewritten in terms of \( t \) as \( \lim _{t \rightarrow -\infty} e^{t} \).

Step 3: Evaluate the limit

Using the known limit \( \lim _{t \rightarrow -\infty} e^{t} = 0 \), we conclude that \( \lim _{x \rightarrow 0^{-}} e^{2 / x} = 0 \).

Final Answer

\(\boxed{0}\)

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