Transcript text: Evaluate $\lim _{x \rightarrow 0^{-}} e^{2 / x}$
If we let $t=\frac{2}{x}$, we know that $t \rightarrow-\infty$ as $x \rightarrow 0^{-}$. Therefore, by $\lim _{x \rightarrow-\infty} e^{x}=0$,
\[
\lim _{x \rightarrow 0^{-}} e^{2 / x}=\lim _{t \rightarrow-\infty} e^{t}=\square
\]