Questions: Use the following information to answer the next question This simplified diagram shows the cell used in the Chlor-Alkali process (electrolysis of sodium chloride solution) at the Dow Chemical Plant in Fort Saskatchewan, Alberta, 17. Litmus paper touched to product III would turn and if it was touched to some of the vapor present in product I it would turn The statement above is best completed by the answers in row:
Row 1 II
red blue
blue no change
red no change
blue red
Transcript text: Use the following information to answer the next question This simplified diagram shows the cell used in the Chlor-Alkali process (electrolysis of sodium chloride solution) at the Dow Chemical Plant in Fort Saskatchewan, Alberta, 17. Litmus paper touched to product III would turn $\qquad$ and if it was touched to some of the vapor present in product I it would turn $\qquad$ The statement above is best completed by the answers in row: \begin{tabular}{|c|l|l|} \hline Row & \multicolumn{1}{|c|}{1} & \multicolumn{1}{|c|}{ II } \\ \hline$\square$ & red & blue \\ \hline$\square$ & blue & no change \\ \hline$\square$ & red & no change \\ \hline$\square$ & blue & red \\ \hline \end{tabular}
Solution
Solution Steps
Step 1: Identify the Products in the Chlor-Alkali Process
The diagram shows the electrolysis of sodium chloride solution (brine) in the Chlor-Alkali process. The products are:
Product I: Chlorine gas (Cl₂)
Product II: Hydrogen gas (H₂)
Product III: Sodium hydroxide (NaOH)
Step 2: Determine the Effect of Litmus Paper on Product III
Product III is sodium hydroxide (NaOH), which is a strong base. When litmus paper is touched to a basic solution:
Red litmus paper turns blue.
Blue litmus paper remains blue.
Step 3: Analyze the Vapor Present in Product III
Since Product III is sodium hydroxide, the vapor present would be water vapor (H₂O) due to the aqueous nature of the solution.
Final Answer
Row I: Red litmus paper will turn blue.
Row II: Blue litmus paper will show no change.