Questions: Point D is located on MV. The coordinates of D are (0,-3/4). What ratio relates MD to DV?
Transcript text: Point $D$ is located on $\overline{M V}$. The coordinates of $D$ are $\left(0,-\frac{3}{4}\right)$. What ratio relates $M D$ to $D V$ ?
Solution
Solution Steps
Step 1: Find the coordinates of M and V.
From the graph, the coordinates of point M are (-3, 2) and the coordinates of point V are (2, -2).
Step 2: Calculate the distance between M and D.
The coordinates of M are (-3, 2) and the coordinates of D are (0, -3/4).
Using the distance formula:
\(MD = \sqrt{(0 - (-3))^2 + (-\frac{3}{4} - 2)^2}\)
\(MD = \sqrt{(3)^2 + (-\frac{11}{4})^2}\)
\(MD = \sqrt{9 + \frac{121}{16}}\)
\(MD = \sqrt{\frac{144 + 121}{16}}\)
\(MD = \sqrt{\frac{265}{16}}\)
\(MD = \frac{\sqrt{265}}{4}\)
Step 3: Calculate the distance between D and V.
The coordinates of D are (0, -3/4) and the coordinates of V are (2, -2).
Using the distance formula:
\(DV = \sqrt{(2 - 0)^2 + (-2 - (-\frac{3}{4}))^2}\)
\(DV = \sqrt{2^2 + (-\frac{5}{4})^2}\)
\(DV = \sqrt{4 + \frac{25}{16}}\)
\(DV = \sqrt{\frac{64 + 25}{16}}\)
\(DV = \sqrt{\frac{89}{16}}\)
\(DV = \frac{\sqrt{89}}{4}\)