To determine when the baseball first reaches a height of 75 feet, we start with the height function given by
\[
y = -5t^{2} + 20t + 60
\]
We set this equal to 75 feet:
\[
-5t^{2} + 20t + 60 = 75
\]
Next, we simplify the equation by moving 75 to the left side:
\[
-5t^{2} + 20t + 60 - 75 = 0
\]
This simplifies to:
\[
-5t^{2} + 20t - 15 = 0
\]
We factor the polynomial \( -5t^{2} + 20t - 15 \). The factored form is:
\[
-5(t - 3)(t - 1) = 0
\]
Setting each factor equal to zero gives us the solutions:
\[
t - 3 = 0 \quad \Rightarrow \quad t = 3
\]
\[
t - 1 = 0 \quad \Rightarrow \quad t = 1
\]
The solutions for \( t \) are \( t = 1 \) seconds and \( t = 3 \) seconds. The first time the baseball reaches a height of 75 feet is:
\[
t = 1 \text{ seconds}
\]