Questions: UAM Acceleration Problems Always show your work ... and don't forget units 1. An object starts at an initial velocity of +6.0 m / s and accelerates at a rate of +3.0 m / s / s for 4 seconds. a) Fill out the data table to the right, showing the instantaneous velocity for each second. b) Complete a numerically accurate (quantitative) instantaneous velocity vs. clock reading graph. c) Recalling that displacement is the area under the V vs. t graph, calculate the displacement of the object during the 4 seconds of elapsed time. Clearly show your calculations units. d) A student wants to calculate displacement by using d=vt=(6 m / s)(4 s). What's wrong with this approach? Clock Reading (s) Velocity (m / s) 0 +6.0 m / s 1 +4.0 m / s 2 +12.0 m / s 3 +15.0 m / s 4 +18.0 m / s 2. A car initially moving at +10.0 m / s constantly accelerates at a rate of -2.0 m / s^2 until it stops. a) Fill out the data table to the right to determine how much time it will take the car to stop. b) Complete a quantitative instantaneous velocity vs. clock reading graph. c) Use the graph to determine the displacement of the object during the entire motion. Show your calculations units. d) Determine the displacement during each second individually. Check to see that all of these sum up to the total displacement calculated in c ). 0-1 sec 1-2 sec 2-3 sec 3-4 sec 4-5 sec 0-5 sec

UAM Acceleration Problems Always show your work ... and don't forget units 1. An object starts at an initial velocity of +6.0 m / s and accelerates at a rate of +3.0 m / s / s for 4 seconds. a) Fill out the data table to the right, showing the instantaneous velocity for each second. b) Complete a numerically accurate (quantitative) instantaneous velocity vs. clock reading graph. c) Recalling that displacement is the area under the V vs. t graph, calculate the displacement of the object during the 4 seconds of elapsed time. Clearly show your calculations  units. d) A student wants to calculate displacement by using d=vt=(6 m / s)(4 s). What's wrong with this approach? Clock Reading (s)  Velocity (m / s) 0  +6.0 m / s 1  +4.0 m / s 2  +12.0 m / s 3  +15.0 m / s 4  +18.0 m / s 2. A car initially moving at +10.0 m / s constantly accelerates at a rate of -2.0 m / s^2 until it stops. a) Fill out the data table to the right to determine how much time it will take the car to stop. b) Complete a quantitative instantaneous velocity vs. clock reading graph. c) Use the graph to determine the displacement of the object during the entire motion. Show your calculations  units. d) Determine the displacement during each second individually. Check to see that all of these sum up to the total displacement calculated in c ). 0-1 sec  1-2 sec  2-3 sec  3-4 sec  4-5 sec  0-5 sec
Transcript text: UAM Acceleration Problems Always show your work ... and don't forget units 1. An object starts at an initial velocity of $+6.0 \mathrm{~m} / \mathrm{s}$ and accelerates at a rate of $+3.0 \mathrm{~m} / \mathrm{s} / \mathrm{s}$ for 4 seconds. a) Fill out the data table to the right, showing the instantaneous velocity for each second. b) Complete a numerically accurate (quantitative) instantaneous velocity vs. clock reading graph. c) Recalling that displacement is the area under the V vs. t graph, calculate the displacement of the object during the 4 seconds of elapsed time. Clearly show your calculations \& units. d) A student wants to calculate displacement by using $\mathrm{d}=\mathrm{vt}=(6 \mathrm{~m} / \mathrm{s})(4 \mathrm{~s})$. What's wrong with this approach? \begin{tabular}{c|l} Clock Reading (s) & Velocity $(\mathrm{m} / \mathrm{s})$ \\ \hline 0 & $+6.0 \mathrm{~m} / \mathrm{s}$ \\ 1 & $+4.0 \mathrm{~m} / \mathrm{s}$ \\ 2 & $+12.0 \mathrm{~m} / \mathrm{s}$ \\ 3 & $+15.0 \mathrm{~m} / \mathrm{s}$ \\ 4 & $+18.0 \mathrm{~m} / \mathrm{s}$ \end{tabular} 2. A car initially moving at $+10.0 \mathrm{~m} / \mathrm{s}$ constantly accelerates at a rate of $-2.0 \mathrm{~m} / \mathrm{s}^{2}$ until it stops. a) Fill out the data table to the right to determine how much time it will take the car to stop. b) Complete a quantitative instantaneous velocity vs. clock reading graph. c) Use the graph to determine the displacement of the object during the entire motion. Show your calculations \& units. d) Determine the displacement during each second individually. Check to see that all of these sum up to the total displacement calculated in c ). \begin{tabular}{|l|l|l|l|l|l|} \hline $0-1 \mathrm{sec}$ & $1-2 \mathrm{sec}$ & $2-3 \mathrm{sec}$ & $3-4 \mathrm{sec}$ & $4-5 \mathrm{sec}$ & $0-5 \mathrm{sec}$ \\ \hline & & & & & \\ \hline \end{tabular}
failed

Solution

failed
failed

Solution Steps

Step 1: Calculate the velocity at each second

The initial velocity is +3.0 m/s and the acceleration is +6.0 m/s². The velocity at each second can be calculated using the formula:

v = u + at

where:

  • v = final velocity
  • u = initial velocity
  • a = acceleration
  • t = time

At t = 0s, v = 3.0 m/s At t = 1s, v = 3.0 + 6.0 * 1 = 9.0 m/s At t = 2s, v = 3.0 + 6.0 * 2 = 15.0 m/s At t = 3s, v = 3.0 + 6.0 * 3 = 21.0 m/s At t = 4s, v = 3.0 + 6.0 * 4 = 27.0 m/s

Step 2: Plot the velocity vs. time graph

The graph should be plotted with time (in seconds) on the x-axis and velocity (in m/s) on the y-axis. The points to plot are (0, 3), (1, 9), (2, 15), (3, 21), and (4, 27). The graph should be a straight line, as the object is undergoing constant acceleration.

Step 3: Calculate the displacement using the graph

The displacement is the area under the velocity-time graph. Since the graph is a trapezoid, we can calculate its area using the formula:

Area = (1/2) * (sum of parallel sides) * height

In this case, the parallel sides are the initial and final velocities (3 m/s and 27 m/s), and the height is the time (4 s).

Displacement = (1/2) * (3 + 27) * 4 = 60 m

Final Answer:

  1. The velocities are 3.0 m/s, 9.0 m/s, 15.0 m/s, 21.0 m/s and 27.0 m/s at t=0s, 1s, 2s, 3s, and 4s, respectively.
  2. A graph should be created using these velocity points over time, which will show a linear relationship.
  3. The displacement of the object is 60 m.
Was this solution helpful?
failed
Unhelpful
failed
Helpful