The initial velocity is +3.0 m/s and the acceleration is +6.0 m/s². The velocity at each second can be calculated using the formula:
v = u + at
where:
- v = final velocity
- u = initial velocity
- a = acceleration
- t = time
At t = 0s, v = 3.0 m/s
At t = 1s, v = 3.0 + 6.0 * 1 = 9.0 m/s
At t = 2s, v = 3.0 + 6.0 * 2 = 15.0 m/s
At t = 3s, v = 3.0 + 6.0 * 3 = 21.0 m/s
At t = 4s, v = 3.0 + 6.0 * 4 = 27.0 m/s
The graph should be plotted with time (in seconds) on the x-axis and velocity (in m/s) on the y-axis. The points to plot are (0, 3), (1, 9), (2, 15), (3, 21), and (4, 27). The graph should be a straight line, as the object is undergoing constant acceleration.
The displacement is the area under the velocity-time graph. Since the graph is a trapezoid, we can calculate its area using the formula:
Area = (1/2) * (sum of parallel sides) * height
In this case, the parallel sides are the initial and final velocities (3 m/s and 27 m/s), and the height is the time (4 s).
Displacement = (1/2) * (3 + 27) * 4 = 60 m
- The velocities are 3.0 m/s, 9.0 m/s, 15.0 m/s, 21.0 m/s and 27.0 m/s at t=0s, 1s, 2s, 3s, and 4s, respectively.
- A graph should be created using these velocity points over time, which will show a linear relationship.
- The displacement of the object is 60 m.