Questions: Et 208V It A Rt Ω Pt W E1 V I1 A R1 150 Ω P1 w E2 V I2 A R2 8000 Ω P2 W E3 V I3 A R3 5050 Ω P3 W E4 V I4 A R4 65500 Ω P4 W E5 V I5 A R5 2500 Ω P5 W E6 V I6 A R6 2300 Ω P6 W

Transcript text: $E_{t}$ 208__V $I_{t}$ A $\mathbf{R}_{\mathrm{t}}$ $\Omega \quad P_{t}$ W $\mathrm{E}_{1}$ V $\mathrm{I}_{1}$ A $\mathrm{R}_{1} \_\mathbf{1 5 0}_{-} \Omega \quad \mathrm{P}_{1}$ w $\mathbf{E}_{2}$ V $I_{2}$ A $\mathrm{R}_{2} \_8000 \_\Omega \mathrm{P}_{2}$ W $\mathbf{E}_{3}$ V $\mathrm{I}_{3}$ A $\mathrm{R}_{3} \mathbf{5}^{5050 \_} \boldsymbol{\Omega} \mathrm{P}_{3}$ W E4 V $\mathrm{I}_{4}$ A $\mathrm{R}_{4} \mathbf{6 5 5 0 0}_{-} \boldsymbol{\Omega} \mathrm{P}_{4}$ W $\mathrm{E}_{5}$ V I5 A $\mathrm{R}_{5} \mathbf{2 5 0 0}_{-} \Omega \mathrm{P}_{5}$ W E6 V $I_{6}$ A $\mathrm{R}_{6} \mathbf{2 3 0 0}_{\mathbf{2}} \Omega \mathrm{P}_{6}$ W

Solution

Solution Steps

Step 1: Calculate the equivalent resistance of resistors R1 and R2.

R1 and R2 are in series, so their equivalent resistance is R1+R2 = 150Ω + 8000Ω = 8150Ω

Step 2: Calculate the equivalent resistance of resistors R4 and R5.

R4 and R5 are in series, so their equivalent resistance is R4+R5 = 6500Ω + 2500Ω = 9000Ω.

Step 3: Calculate the equivalent resistance of the R1, R2, R3, R4 and R5 combination.

The equivalent resistance from Step 1 (R1 and R2), the equivalent resistance from Step 2 (R4 and R5) and R3 are in parallel. Let Rx be the equivalent resistance of this combination: 1/Rx = 1/8150 + 1/5050 + 1/9000 1/Rx ≈ 0.0001227 + 0.000198 + 0.0001111 1/Rx ≈ 0.0004318 Rx ≈ 2316 Ω