Questions: Find the percent of the total area under the standard normal curve between the following z-scores. z=-1.2 and z=-0.75 Click here to see page 1 of the table for areas under the standard normal curve. Click here to see page 2 of the table for areas under the standard normal curve. The percent of the total area between z=-1.2 and z=-0.75 is % (Round to the nearest integer.)

Solution Steps

We need to find the percent of the total area under the standard normal curve between the z-scores \( z = -1.2 \) and \( z = -0.75 \).

Using the cumulative distribution function \( \Phi(z) \) for the standard normal distribution, we calculate the probabilities at the given z-scores:

\[ P = \Phi(Z_{end}) - \Phi(Z_{start}) = \Phi(-0.75) - \Phi(-1.2) \]

From the calculations, we find:

\[ P = 0.1116 \]

To express the probability as a percentage, we multiply by 100:

\[ \text{Percent} = P \times 100 = 0.1116 \times 100 = 11.16 \]

Rounding to the nearest integer gives us:

\[ \text{Percent} \approx 11\% \]

Final Answer