The system of equations can be represented in matrix form as \(Ax = B\), where \(A = \begin{pmatrix}4 & 2 \\ 6 & -1\end{pmatrix}\) and \(B = \begin{pmatrix}4 \\ 8\end{pmatrix}\).
Step 2: Check the Determinant of A
The determinant of matrix A is \(det(A) = -16.0\). Since \(det(A) \neq 0\), the system has a unique solution.
Step 3: Apply Cramer's Rule
Using Cramer's Rule, we calculate the determinants \(det(A1) = -20.0\) and \(det(A2) = 8.0\).
Thus, the solution is \(x = 1\) and \(y = -0\), rounded to 0 decimal places.
Final Answer:
The solution to the system of equations is \(x = 1\), \(y = -0\).