Questions: Question 7 A 1 M H2SO4 will be used in preparing the sodium oxalate solution for titration in this experiment. What volume of 6 M H2SO4 is required to prepare 200 mL of 1 M H2SO4 solution. (A) 0.03333 mL (B) 1200 mL (C) 33.33 mL (D) 1.2 mL

Question 7
A 1 M H2SO4 will be used in preparing the sodium oxalate solution for titration in this experiment. What volume of 6 M H2SO4 is required to prepare 200 mL of 1 M H2SO4 solution.
(A) 0.03333 mL
(B) 1200 mL
(C) 33.33 mL
(D) 1.2 mL

Transcript text: Question 7 A $1 \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{4}$ will be used in preparing the sodium oxalate solution for titration in this experiment. What volume of $6 \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{4}$ is required to prepare 200 mL of $1 \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{4}$ solution. (A) 0.03333 mL (B) 1200 mL (C) 33.33 mL (D) 1.2 mL

Solution

Solution Steps

Step 1: Identify the given information

We are given:

The concentration of the stock solution: $6 \, \text{M} \, \text{H}_2\text{SO}_4$
The desired concentration of the final solution: $1 \, \text{M} \, \text{H}_2\text{SO}_4$
The volume of the final solution: $200 \, \text{mL}$

Step 2: Use the dilution formula

The dilution formula is: \[ C_1 V_1 = C_2 V_2 \] where:

$C_1$ is the concentration of the stock solution
$V_1$ is the volume of the stock solution needed
$C_2$ is the concentration of the final solution
$V_2$ is the volume of the final solution

Step 3: Substitute the given values into the formula

Substitute $C_1 = 6 \, \text{M}$, $C_2 = 1 \, \text{M}$, and $V_2 = 200 \, \text{mL}$ into the formula: \[ 6 \, \text{M} \times V_1 = 1 \, \text{M} \times 200 \, \text{mL} \]

Step 4: Solve for $V_1$

\[ V_1 = \frac{1 \, \text{M} \times 200 \, \text{mL}}{6 \, \text{M}} \] \[ V_1 = \frac{200}{6} \, \text{mL} \] \[ V_1 = 33.33 \, \text{mL} \]