Questions: barium bromine ○ yes ○ no BaBr2 bromine sodium ○ yes ○ no

barium bromine ○ yes ○ no BaBr2 bromine sodium ○ yes ○ no
Transcript text: \begin{tabular}{|c|c|cc|c|} \hline barium & bromine & ○ yes & $\bigcirc$ no & $\mathrm{BaBr}_{2}$ \\ \hline bromine & sodium & $\bigcirc$ yes & $\bigcirc$ no & $\square$ \\ \hline \end{tabular}
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Solution

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Solution Steps

Step 1: Understanding the Table

The table provided seems to be a part of a chemical reaction or compound formation check. It lists elements and asks whether a compound can be formed, with a column for the resulting compound.

Step 2: Analyzing the First Row

The first row lists "barium" and "bromine" with a checkmark under "yes" and the compound \(\mathrm{BaBr}_{2}\) in the last column. This indicates that barium and bromine can form the compound barium bromide, \(\mathrm{BaBr}_{2}\).

Step 3: Analyzing the Second Row

The second row lists "bromine" and "sodium" with no checkmark under "yes" or "no" and an empty box in the compound column. This suggests that the table is incomplete for this pair. However, bromine and sodium can form sodium bromide, \(\mathrm{NaBr}\).

Final Answer

  1. Barium and bromine form \(\mathrm{BaBr}_{2}\).
  2. Bromine and sodium can form \(\mathrm{NaBr}\).

\[ \boxed{\mathrm{BaBr}_{2}, \mathrm{NaBr}} \]

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