Questions: Solve for t. 8/(2t-8) - 4/(t-4) = 4

Solve for t.
8/(2t-8) - 4/(t-4) = 4
Transcript text: Solve for $t$. \[ \frac{8}{2 t-8}-\frac{4}{t-4}=4 \]
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Solution

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Solution Steps

To solve the equation \(\frac{8}{2t-8} - \frac{4}{t-4} = 4\), we need to find a common denominator and then solve the resulting equation for \(t\).

  1. Identify the common denominator for the fractions.
  2. Combine the fractions over the common denominator.
  3. Simplify the equation and solve for \(t\).
  4. Check for any extraneous solutions by substituting back into the original equation.
Step 1: Identify the Common Denominator

To solve the equation \(\frac{8}{2t-8} - \frac{4}{t-4} = 4\), we first identify the common denominator for the fractions. The denominators are \(2t-8\) and \(t-4\). Notice that \(2t-8 = 2(t-4)\).

Step 2: Combine the Fractions

Rewrite the equation using the common denominator: \[ \frac{8}{2(t-4)} - \frac{4}{t-4} = 4 \] Multiply both sides by the common denominator \(2(t-4)\) to clear the fractions: \[ 8 - 4 \cdot 2 = 4 \cdot 2(t-4) \] Simplify: \[ 8 - 8 = 8(t-4) \] \[ 0 = 8(t-4) \]

Step 3: Solve for \(t\)

Solve the equation \(0 = 8(t-4)\): \[ 0 = 8(t-4) \] \[ t-4 = 0 \] \[ t = 4 \]

Step 4: Check for Extraneous Solutions

Substitute \(t = 4\) back into the original equation to check for extraneous solutions: \[ \frac{8}{2(4)-8} - \frac{4}{4-4} = 4 \] This results in division by zero, which is undefined. Therefore, \(t = 4\) is not a valid solution.

Final Answer

There is no solution to the equation \(\frac{8}{2t-8} - \frac{4}{t-4} = 4\).

\[ \boxed{\text{No solution}} \]

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