Questions: 1. Consider the framing plan below. Assume a Dead Load of 60 PSF. a. Calculate the tributary width for each beam. (5 pts) b. Calculate the end reactions for each beam. (10 pts) c. Draw a Free Body Diagram (FBD) and calculate the end reactions for each girder. ( 25 pts) d. Calculate the total axial load in columns C1 and C2. (10 pts)

Solution Steps

The tributary width for each beam is half the distance to the adjacent beams on either side. Since the beams are spaced at 11'-3" intervals, the tributary width for each W24x53 beam is (11'-3") / 2 = 5'-7.5" = 5.625 ft.

The total load on each W24x53 beam is the dead load multiplied by the tributary width and the beam span (which equals the column spacing). The beam span is 22'-6" = 22.5 ft. Therefore the total load = 60 psf * 5.625 ft * 22.5 ft = 7593.75 lbs.

Since the beams are simply supported, the end reactions are equal to half the total load. Therefore, each end reaction = 7593.75 lbs / 2 = 3796.875 lbs.

Here's a description of the FBD and calculations for the girders:

• FBD: The girders (W36x112) are supported at each end by the columns. The loads acting on the girder are the point loads from the beam reactions, which are calculated in the previous step. There are four beam reactions acting on each girder.

• Calculations: Each beam applies a concentrated load of 3796.875 lbs onto the girder. Since the girder is simply supported and the beams are evenly spaced, the reactions at each end (C1 and C2) are equal to half the total load applied by the beams.

Total load on each girder = 4 beams * 3796.875 lbs/beam = 15187.5 lbs

Reaction at C1 and C2= 15187.5 lbs / 2 = 7593.75 lbs

Final Answer: