Questions: A chemist prepares a solution of barium chlorate (Ba(ClO3)2) by measuring out 58.2 μmol of barium chlorate into a 400. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's barium chlorate solution. Round your answer to 3 significant digits.

Solution Steps

First, convert the amount of barium chlorate from micromoles to moles.

\[ 58.2 \, \mu\text{mol} = 58.2 \times 10^{-6} \, \text{mol} \]

Convert the volume of the solution from milliliters to liters.

\[ 400. \, \text{mL} = 0.400 \, \text{L} \]

Molarity is calculated by dividing the number of moles of solute by the volume of the solution in liters.

\[ \text{Molarity} = \frac{58.2 \times 10^{-6} \, \text{mol}}{0.400 \, \text{L}} = 1.455 \times 10^{-4} \, \text{mol/L} \]

Final Answer