Questions: Write an equation of the line passing through point P(0,1) that is parallel to the line y=-2x+3. An equation is:

Write an equation of the line passing through point P(0,1) that is parallel to the line y=-2x+3.

An equation is:
Transcript text: Write an equation of the line passing through point $P(0,1)$ that is parallel to the line $y=-2 x+3$. An equation is: $\square$
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Solution

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Solution Steps

Step 1: Identify the slope of the given line

The given line is y=2x+3 y = -2x + 3 . The slope of this line is 2-2.

Step 2: Use the point-slope form to find the equation of the parallel line

The line passing through point P(0,1) P(0,1) and parallel to y=2x+3 y = -2x + 3 will have the same slope, 2-2. Using the point-slope form yy1=m(xx1) y - y_1 = m(x - x_1) , where m m is the slope and (x1,y1) (x_1, y_1) is the point, we get: y1=2(x0) y - 1 = -2(x - 0) y1=2x y - 1 = -2x y=2x+1 y = -2x + 1

Final Answer

The equation of the line passing through point P(0,1) P(0,1) that is parallel to the line y=2x+3 y = -2x + 3 is: y=2x+1 y = -2x + 1

{"axisType": 3, "coordSystem": {"xmin": -5, "xmax": 5, "ymin": -5, "ymax": 5}, "commands": ["y = -2x + 3", "y = -2x + 1"], "latex_expressions": ["y=2x+3y = -2x + 3", "y=2x+1y = -2x + 1"]}

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