Questions: How many minutes (min) will it take for a car that is moving at 5.4 × 10 mi / h to travel 250. km?

How many minutes (min) will it take for a car that is moving at 5.4 × 10 mi / h to travel 250. km?
Transcript text: How many minutes $(\min )$ will it take for a car that is moving at $5.4 \times 10 \mathrm{mi} / \mathrm{h}$ to travel 250. km?
failed

Solution

failed
failed

Solution Steps

Step 1: Convert Speed from Miles per Hour to Kilometers per Hour

The speed of the car is given as \(5.4 \times 10 \, \text{mi/h}\). First, convert this speed to kilometers per hour using the conversion factor \(1 \, \text{mi} = 1.60934 \, \text{km}\).

\[ 5.4 \times 10 \, \text{mi/h} = 54 \, \text{mi/h} \]

\[ 54 \, \text{mi/h} \times 1.60934 \, \text{km/mi} = 86.1044 \, \text{km/h} \]

Step 2: Convert Distance from Kilometers to Miles

The distance to be traveled is 250 km. Convert this distance to miles using the conversion factor \(1 \, \text{mi} = 1.60934 \, \text{km}\).

\[ 250 \, \text{km} \times \frac{1 \, \text{mi}}{1.60934 \, \text{km}} \approx 155.343 \, \text{mi} \]

Step 3: Calculate Time in Hours

Calculate the time it takes to travel 155.343 miles at a speed of 54 mi/h.

\[ \text{Time in hours} = \frac{155.343 \, \text{mi}}{54 \, \text{mi/h}} \approx 2.8758 \, \text{hours} \]

Step 4: Convert Time from Hours to Minutes

Convert the time from hours to minutes.

\[ 2.8758 \, \text{hours} \times 60 \, \text{minutes/hour} = 172.548 \, \text{minutes} \]

Final Answer

The time it will take for the car to travel 250 km is approximately \(\boxed{172.548 \, \text{minutes}}\).

Was this solution helpful?
failed
Unhelpful
failed
Helpful

Questions asked by other users

failedAnswered
Multiple Choice Question Which is the main role of proteins in cells? Long term energy molecules. Contain genetic information. Structural and functional molecules. Quick energy source for the cell. Need help? Review these concept resources.
failedAnswered
After collecting n=20 data points, suppose you computed r=-0.85. Using the critical values table below, determine if the value of r is significant or not. df, CV + and -, df, CV + and -, df, CV + and -, df, CV + and - 1, 0.997, 11, 0.555, 21, 0.413, 40, 0.304 2, 0.950, 12, 0.532, 22, 0.404, 50, 0.273 3, 0.878, 13, 0.514, 23, 0.396, 60, 0.250 4, 0.811, 14, 0.497, 24, 0.388, 70, 0.232 5, 0.754, 15, 0.482, 25, 0.381, 80, 0.217 6, 0.707, 16, 0.468, 26, 0.374, 90, 0.205 7, 0.666, 17, 0.456, 27, 0.367, 100, 0.195 8, 0.632, 18, 0.444, 28, 0.361, 9, 0.602, 19, 0.433, 29, 0.355, 10, 0.576, 20, 0.423, 30, 0.349, Select the correct answer below. r is significant because it is between the positive and negative critical values. r is not significant because it is between the positive and negative critical values. r is significant because it is not between the positive and negative critical values. r is not significant because it is not between the positive and negative critical values.
failedAnswered
The Federal Trade Commission, Consumer Financial Protection Bureau, FDA US Department of Justice enforce: - all laws - federal consumer protection laws - antitrust laws - tax laws
failedAnswered
Find the union of the sets. 2,4,6 ∪ 1,3,5,7 Choose the correct answer below. A. 2,4,6 ∪ 1,3,5,7 = ∅ B. 2,4,6 ∪ 1,3,5,7 = 1,3,5,7 C. 2,4,6 ∪ 1,3,5,7 = 1,2,3,4,5,6,7 D. 2,4,6 ∪ 1,3,5,7 = 2,4,6
failedAnswered
The average American gets a haircut every 38 days. Is the average smaller for college students? The data below shows the results of a survey of 16 college students asking them how many days elapse between haircuts. Assume that the distribution of the population is normal. 43,44,30,38,35,26,27,39, 26,24,34,33,30,26,30,38 The final conclusion is a. The data suggest the population mean is significantly lower than 38 at a=0.01, so there is sufficient evidence to conclude that the population mean number of days between haircuts for college students is lower than 38. b. The data suggest the population mean number of days between haircuts for college students is not significantly lower than 38 at a=0.01, so there is insufficient evidence to conclude that the population mean number of days between haircuts for college students is lower than 38. c. The data suggest the population mean is not significantly lower than 38 at α= 0.01 , so there is sufficient evidence to conclude that the population mean number of days between haircuts for college students is lower than 38.